Let's solve this by substitution.
y is given by the 2nd eqn as y = (1/3)x + 7. Subst. (1/3)x + 7 into the first eqn as a replacement for y: x + 9( (1/3)x + 7) = 3.
clear out fractions by mult. all 3 terms by 3: 3x + 9x + 63 = 3
Combine like terms: 12x = -60. Then x = -5
Find y by subst. -5 for x in the 2nd equation: y = (1/3)(-5) + 7
= -5/3 + 35/3 = 30/3 = 10.
Thus, the solution (x,y) of this system is (-5,10).
A line parallel to y = 0.6x + 3 will be of the form:
where k is a constant.
It passes through (-3,-5)
Thus,
I think it’s A. i’m not very sure tho
Answer:
If you mean "How do I write an inequality?", the answer is COEFFICIENTxVARIABLE {any symbol} COEFFICIENTxVARIABLE >/< INTEGER
In other words, you should have something like this: -3x + 4v < 63
Or this: 51x - 16v > 11
Or anything along those lines.
Answer:
3/1
Step-by-step explanation:
