To determine the number of years to reach a certain number of population, we need an equation which would relate population and the number of years. For this problem, we use the given equation:
<span>P=1,000,000(1.035)^x
We substitute the population desired to be reached to the equation and evaluate the value of x.
</span>P=1,000,000(1.035)^x
1400000=1,000,000(1.035)^x
7/5 = 1.035^x
ln 7/5 = ln 1.035^x
x = ln 7/5 / ln 1.035
x = 9.78
Therefore, the number of years needed to reach a population of 1400000 with a starting population of 1000000 would be approximately 10 years.
This question is a very hard and difficult one to answer. The main reason
<span>is because you said "the right rectangular prism shown" and then you didn't </span>
show it. So all I can tell you is this:
-- The volume of each small cube is
(1/4) x (1/4) x (1/4) = 1/64 cubic inch .
-- The volume of the right rectangular prism that's not shown is
<span> (length in inches) x (width in inches) x (height in inches) cubic inches. </span>
The number of small cubes needed to fill the invisible right rectangular prism is ...
(volume of the missing right rectangular prism)
divided by
(volume of each small cube) .
That's
<span> (volume of the alleged right rectangular prism) </span>
divided by
(1/64 cubic inch)
<span>= </span>(64) times (volume of the rumored right rectangular prism)<span> .</span>
y = 6 - 3x
x + y = 62
Since we already know the value of y, we can use substitution to find the value of x.
x + 6 - 3x = 62
<em><u>Subtract 6 from both sides.</u></em>
x - 3x = 56
<em><u>Combine like terms.</u></em>
-2x = 56
<em><u>Divide both sides by -2</u></em>
x = -28
Now that we know the value of x, we can solve for the value of y.
x + y = 62
-28 + y = 62
<em><u>Add 28 to both sides</u></em>
y = 90
The value of y is 90, and the value of x is -28 (this is your answer)
To make sure that these values are correct, we can plug them into the original equations.
y = 6 - 3x
x + y = 62
90 = 6 - 3(-28)
90 = 90 √ this is correct
-28 + 90 = 62
62 = 62 √ this is also correct
