y = 6 - 3x
x + y = 62
Since we already know the value of y, we can use substitution to find the value of x.
x + 6 - 3x = 62
<em><u>Subtract 6 from both sides.</u></em>
x - 3x = 56
<em><u>Combine like terms.</u></em>
-2x = 56
<em><u>Divide both sides by -2</u></em>
x = -28
Now that we know the value of x, we can solve for the value of y.
-28 + y = 62
<em><u>Add 28 to both sides</u></em>
y = 90
The value of y is 90, and the value of x is -28 (this is your answer)
To make sure that these values are correct, we can plug them into the original equations.
90 = 6 - 3(-28)
90 = 90 √ this is correct
-28 + 90 = 62
62 = 62 √ this is also correct
+= 34
The equation of a circle in standard form is
+=
where (a , b) are the coordinates of the centre and r is the radius
The centre is at the midpoint of the endpoints and the radius is the distance from the centre to either of the 2 endpoints
Using the midpoint formula
midpoint = [(x+, (+
where (,=(3,8) and (,=(-7,2)
centre = ((3-7),(8+2)) = (-2,5)
Calculate r using the distance formula
r = √(-)²+(-)²)
= √((3+2)²+(8-5)²) = √(25+9) = √34 ⇒ r² =(√34)² = 34
equation of circle is : (x+2)²+(y-5)² = 34
Answer:
D and E
Step-by-step explanation:
Perimeter = 4s
4(x + 8)
4x + 32
So you have a scale
you multiply: 8×(3/4)
And your x= 6
or