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Blababa [14]
4 years ago
9

One number is 6 less than 3 times another number and their sum is 62.find the numbers

Mathematics
1 answer:
zysi [14]4 years ago
3 0

y = 6 - 3x

x + y = 62

Since we already know the value of y, we can use substitution to find the value of x.

x + 6 - 3x = 62

<em><u>Subtract 6 from both sides.</u></em>

x - 3x = 56

<em><u>Combine like terms.</u></em>

-2x = 56

<em><u>Divide both sides by -2</u></em>

x = -28

Now that we know the value of x, we can solve for the value of y.

x + y = 62

-28 + y = 62

<em><u>Add 28 to both sides</u></em>

y = 90

The value of y is 90, and the value of x is -28 (this is your answer)

To make sure that these values are correct, we can plug them into the original equations.

y = 6 - 3x

x + y = 62

90 = 6 - 3(-28)

90 = 90 √ this is correct

-28 + 90 = 62

62 = 62 √ this is also correct

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Find the standard form of the equation of the circle with endpoints of a diameter at the points (3,8) and (-7,2)
poizon [28]

(x+2)^{2}+(y-5)^{2}= 34

The equation of a circle in standard form is

(x-a)^{2}+(y-b)^{2}=r^{2}

where (a , b) are the coordinates of the centre and r is the radius

The centre is at the midpoint of the endpoints and the radius is the distance from the centre to either of the 2 endpoints

Using the midpoint formula

midpoint = [\frac{1}{2}(xx_{1}+x_{2}, \frac{1}{2}(y_{1}+y_{2}

where (x_{1},y_{1}=(3,8) and (x_{2},y_{2}=(-7,2)

centre = (\frac{1}{2}(3-7),\frac{1}{2}(8+2)) = (-2,5)

Calculate r using the distance formula

r = √(x_{2}-x_{1})²+(y_{2}-y_{1})²)

= √((3+2)²+(8-5)²) = √(25+9) = √34 ⇒ r² =(√34)² = 34

equation of circle is : (x+2)²+(y-5)² = 34


8 0
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AlexFokin [52]
So because 25%=1/4 we would know to multiply 9*4
Which would get our answer to be 36 :)
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