Rewrite the function f of x equals 4 times one third to the 2 times x power using properties of exponents.
1 answer:
Answer:
Option 1
Step-by-step explanation:
Given : Function f of x equals 4 times one third to the 2 times x power.
To find : Rewrite the function using properties of exponents ?
Solution :
Writing the function in numeric terms,
f of x equals 4 times one third to the 2 times x power
i.e.
Solve the expression,
i.e. f of x equals 4 times one ninth to the x power.
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Answer:
Standard form of the line with point (4,-8) and slope of 1/4 is
-x + 4 y = -36.
Step-by-step explanation:
The slope of the line equation = 1/4
The point is given as (4,-8).
Now, by POINT SLOPE formula,
The line equation with slope m nad point (x0,y0) is given as:
(y - y0) = m (x -x0)
So, the line equation here is given as
Now, the standard form of line equation is Ax + By = C
Here, 4y = x - 36 ⇒ 4y - x = -36
or, -x + 4y = -36 is the standard form.
Hence,standard form of the line with point (4,-8) and slope of 1/4
is -x + 4y = -36.
408.454 cubic inches of air is surrounding the ball in the box
Step-by-step explanation:
When a sphere is inscribed in a cube and touching all of its faces, then
- The diameter of the sphere = the side of the cube
- The empty volume of the cube is the difference between the volume of the cube and the volume of the sphere
∵ The basketball is shaped a sphere
∵ The box is shaped a cube
∵ The ball touching every wall of the box
∴ The diameter of the ball = the side of the box
∵ The length of one side of the cube = 9.5 inches
∴ The diameter of the ball = 9.5 inches
∵ The diameter of the ball = 2 r, where r is the radius of the ball
∴ 9.5 = 2 r
- Divide both sides by 2
∴ r = 4.75 inches
∵ The volume of the air that surrounded the ball in the box =
volume of the box - volume of the ball
∵ Volume box (cube) = s³
∵ s = 9.5 inches
∴ Volume of the box = (9.5)³
∴ Volume of the box = 857.375 inches³
∵ Volume the ball (sphere) = π r³
∵ r = 4.75
∴ Volume the ball = (π)(4.75)³
∴ Volume the ball = 448.921 inches³
Substitute the values of the volumes of the box and the ball in the rule above
∴ The volume of the air = 857.375 - 448.921
∴ The volume of the air = 408.454 inches³
408.454 cubic inches of air is surrounding the ball in the box
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