Answer:
The original side length of the square was 9 ft
Step-by-step explanation:
Consider that the square was initially of side length "x" (our unknown). Then the sides were all increased by 5 ft, and now the perimeter (addition of all four sides) of the square render 56 ft.
Let's write an equation that represents the addition of the four sides of this new rectangle, and set it equal to 56 ft. Then solve for the unknown "x":
Therefore, the original side of the square was 9 ft.
5x + 3y = - 53
the equation of a line in ' slope- intercept form ' is y = mx + c
where m is the slope and c the y-intercept
rearrange 3x - 5y = - 15 into this form to obtain m → (subtract 3x from both sides)
- 5y = - 3x - 15 → divide all terms by - 5 )
y = x + 3 → in slope-intercept form with m =
given a line with slope m then the slope m₁ of a line perpendicular to it is
m₁ = - = - 1 ÷
= -
partial equation is y = - x + c
to find c substitute ( - 7, - 6) into the partial equation
- 6 = + c ⇒ c = - 6 -
= -
y = - x -
→ in slope intercept form
multiply all terms by 3
3y = - 5x - 53 → ( add 5x to both sides )
5x + 3y = - 53 → in standard form
8 5/12 because you have to get the 3 fractions denomenators to be the same. so 3, 4 and 2 all go into 12 then you need go multiply the top by the same number as the bottom
