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2 years ago

5

36abc + 54ad i don't know the answer

2 answers:

AnnyKZ [126]2 years ago

6 0

Answer:

2bc

Step-by-step explanation:

can't tell how i got it but 2bc is the answer

Genrish500 [490]2 years ago

4 0

Hello, I am BrotherEye

Answer:

The soulution to this question is 18a * (2bc +3d)

Step-by-step explanation:

I used a Grpahing calculator to solve this problem.

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Please help quickly Evaluate the expression: -|5+(2-8)|+|7(2-8)|

DanielleElmas [232]

$\displaystyle\\-\Big|5+(2-8)\Big|+\Big|7(2-8)\Big|=\\\\=-\Big|5+(-6)\Big|+\Big|7\times(-6)\Big|=\\\\=-\Big|-1\Big|+\Big|-42\Big|=\\\\=-(+1)+42=\\\\=-1+42=\boxed{\bf41}$

4 0

2 years ago

Read 2 more answers

Find three positive numbers whose sum is 140 and whose product is a maximum. (Enter your answers as a comma-separated list.)

Paladinen [302]

Answer:

$\frac{140}{3}, \frac{140}{3}, \frac{140}{3}$

Step-by-step explanation:

Let the numbers be $x, y\ and\ z.$

Such that:

$x + y + z = 140$

Make z the subject

$z = 140 -x - y$

For their product to be maximum, we have:

$f(x,y,z) = xyz$

Substitute $z = 140 -x - y$ in $f(x,y,z) = xyz$

$f(x,y) = xy(140 - x - y)$

Open bracket

$f(x,y) = 140xy - x^2y - xy^2$

Differentiate w.r.t x and y

$f_x=140y - 2xy - y^2$

$f_y=140x - x^2 - 2xy$

Since the products are maximum, then $f_x = f_y = 0$

For $f_x=140y - 2xy - y^2$

$140y - 2xy - y^2 = 0$

Factorize:

$y(140 - 2x - y) = 0$

Split

$y = 0\ or\ 140 - 2x - y = 0$

Make y the subject

$y = 0\ or\ y = 140 - 2x$

For $f_y=140x - x^2 - 2xy$

$140x - x^2 - 2xy = 0$

---------------------------------------------------

Substitute y = 0

$140x - x^2 -2x*0 = 0$

$140x - x^2 = 0$

Factorize

$x(140 - x)= 0$

$x = 0\ or\ 140-x = 0$

$x = 0\ or\ x = 140$

---------------------------------------------------

Substitute $y = 140 - 2x$

$140x - x^2 - 2xy = 0$

$140x - x^2 - 2x(140 - 2x) = 0$

$140x - x^2 - 280x + 4x^2 = 0$

Re-arrange

$4x^2 -x^2 +140x - 280x = 0$

$3x^2 -140x = 0$

Factor x out

$x(3x - 140) = 0$

Divide through by x

$3x - 140 = 0$

$3x = 140$

$x = \frac{140}{3}$

Recall that: $y = 140 - 2x$

$y = 140 - 2 * \frac{140}{3}$

$y = 140 - \frac{280}{3}$

Take LCM

$y = \frac{140*3-280}{3}$

$y = \frac{140}{3}$

Recall that:

$z = 140 -x - y$

$z = 140 - \frac{140}{3} - \frac{140}{3}$

Take LCM

$z = \frac{3 * 140- 140 - 140}{3}$

$z = \frac{140}{3}$

Hence, the numbers are:

$\frac{140}{3}, \frac{140}{3}, \frac{140}{3}$

8 0

2 years ago

Marriana buys 3 3/4 feet of rope. How many inches of rope does she buy?

SVEN [57.7K]

Answer:

45

Step-by-step explanation:

4 0

2 years ago

#HP Help.Please

densk [106]

Answer:

B = minus 15 is greater than 21 = as the line stops at 3^2 and shows 15 with shaded circle

It stops at -5^2 open circle and -5 x -5 = = 25

So if we use a value more than this -4.6 x -4.6 = 21

3 0

2 years ago

Read 2 more answers

What is the solution to the equation?<br> 3 x – 1 = 8<br><br> Please help

masya89 [10]

Answer:

Step-by-step explanation:

Here you go mate

Step 1

3x-1=8 Equation/Question

Step 2

3x-1=8 Simplify

3x-1=8

Step 3

3x-1=8 Add 1 to sides

3x=9

Step 4

3x=9 Divide sides by 3

answer

x=3

Hope this helps

3 0

2 years ago