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hichkok12 [17]
3 years ago
8

It is given that the area of a football field is 7.8 km².

Mathematics
2 answers:
hram777 [196]3 years ago
8 0

Answer:

Step-by-step explanation:

2437.5m

Wittaler [7]3 years ago
7 0

Answer:

2437.5m

Step-by-step explanation:

Assuming a rectangular shape, we have

Area=w×h, where w is the width anh h the length.

1km²=1000²m²=10⁶m²

7.8km²=7.8×10⁶=78×10⁵=3200×h

78×1000=32h

h=78000/32=2437.5m

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The denominator of a fraction in the simplest form is greater than the numerator by 1. If 4 is added to the numerator, and 3 is
Fantom [35]

Answer:

Step-by-step explanation:

Let the original fraction is: x/ x-1

And we have that:

  • 4 is added to the numerator => new numerator is: x+4
  • 3 is subtracted from the denominator => new denominator is: x -1-3 = x -4

the fraction itself is increased by 2\frac{1}{6}

<=> \frac{x}{x-1} *2\frac{1}{6} = \frac{x+4}{x-4}

<=> 7x^{2} -70x +24 = 0

Solve for X then we substitue into the original fraction

4 0
3 years ago
If 2x = 3y + 11 and 2^x = 2^4(y+1), determine the value of x+y
Pachacha [2.7K]

Answer:

3^7

Step-by-step explanation:

https://dlsfile.com/dd/MTQ1ODE5a3Bjd2hiaGxmXzM0MTMyNQ

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2 years ago
Calculus hw, need help asap with steps.
nikdorinn [45]

Answers are in bold

S1 = 1

S2 = 0.5

S3 = 0.6667

S4 = 0.625

S5 = 0.6333

=========================================================

Explanation:

Let f(n) = \frac{(-1)^{n+1}}{n!}

The summation given to us represents the following

\displaystyle \sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{n!}=\sum_{n=1}^{\infty} f(n)\\\\\\\displaystyle \sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{n!}=f(1) + f(2)+f(3)+\ldots\\\\

There are infinitely many terms to be added.

-------------------

The partial sums only care about adding a finite amount of terms.

The partial sum S_1 is the sum of the first term and nothing else. Technically it's not really a sum because it doesn't have any other thing to add to. So we simply say S_1 = f(1) = 1

I'm skipping the steps to compute f(1) since you already have done so.

-------------------

The second partial sum is when things get a bit more interesting.

We add the first two terms.

S_2 = f(1)+f(2)\\\\S_2 = 1+(-\frac{1}{2})\\\\S_2 = \frac{1}{2}\\\\S_2 = 0.5\\\\\\

The scratch work for computing f(2) is shown in the diagram below.

-------------------

We do the same type of steps for the third partial sum.

S_3 = f(1)+f(2)+f(3)\\\\S_3 = 1+(-\frac{1}{2})+\frac{1}{6}\\\\S_3 = \frac{2}{3}\\\\S_3 \approx 0.6667\\\\\\

The scratch work for computing f(3) is shown in the diagram below.

-------------------

Now add the first four terms to get the fourth partial sum.

S_4 = f(1)+f(2)+f(3)+f(4)\\\\S_4 = 1+(-\frac{1}{2})+\frac{1}{6}-\frac{1}{24}\\\\S_4 = \frac{5}{8}\\\\S_4 \approx 0.625\\\\\\

As before, the scratch work for f(4) is shown below.

I'm sure you can notice by now, but the partial sums are recursive. Each new partial sum builds upon what is already added up so far.

This means something like S_3 = S_2 + f(3) and S_4 = S_3 + f(4)

In general, S_{n+1} = S_{n} + f(n+1) so you don't have to add up all the first n terms. Simply add the last term to the previous partial sum.

-------------------

Let's use that recursive trick to find S_5

S_5 = [f(1)+f(2)+f(3)+f(4)]+f(5)\\\\S_5 = S_4 + f(5)\\\\S_5 = \frac{5}{8} + \frac{1}{120}\\\\S_5 = \frac{19}{30}\\\\S_5 \approx 0.6333

The scratch work for f(5) is shown below.

7 0
2 years ago
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kaheart [24]

Answer:

Exact Form:

7/ 6

Decimal Form:

1.1

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Mixed Number Form:

1  1/

6

Step-by-step explanation:

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