Answer:
0.75-0.5=0.25
Step-by-step explanation:
Subtract the minimum data value from the maximum data value to find the data range. In this case, the data range is 0.25 or 1/4.
2(3)+4= ......................
6+4=10
Answer:
p = ![\frac{16}{q+1}](https://tex.z-dn.net/?f=%5Cfrac%7B16%7D%7Bq%2B1%7D)
Step-by-step explanation:
Since there are 2 equal roots then the value of the discriminant is zero, that is
b² - 4ac = 0
Given
(q + 1)x² - 8x + p = 0 ← in standard form
with a = q + 1, b = - 8, c = p , then
(- 8)² - 4p(q + 1) = 0
64 - 4p(q + 1) = 0 ( subtract 64 from both sides )
- 4p(q + 1) = - 64 ( divide both sides by - 4 )
p(q + 1) = 16 ( divide both sides by q + 1 )
p = ![\frac{16}{q+1}](https://tex.z-dn.net/?f=%5Cfrac%7B16%7D%7Bq%2B1%7D)
Answer:
Two Angles are Supplementary when they add up to 180 degrees.
Step-by-step explanation:
Answer:
the probability that he length of this component is between 4.98 and 5.02 cm is 0.682 (68.2%)
Step-by-step explanation:
Since the random variable X= length of component chosen at random , is normally distributed, we can define the following standardized normal variable Z:
Z= (X- μ)/σ
where μ= mean of X , σ= standard deviation of X
for a length between 4.98 cm and 5.02 cm , then
Z₁= (X₁- μ)/σ = (4.98 cm - 5 cm)/0.02 cm = -1
Z₂= (X₂- μ)/σ = (5.02 cm - 5 cm)/0.02 cm = 1
therefore the probability that the length is between 4.98 cm and 5.02 cm is
P( 4.98 cm ≤X≤5.02 cm)=P( -1 ≤Z≤ 1) = P(Z≤1) - P(Z≤-1)
from standard normal distribution tables we find that
P( 4.98 cm ≤X≤5.02 cm) = P(Z≤1) - P(Z≤-1) = 0.841 - 0.159 = 0.682 (68.2%)
therefore the probability that he length of this component is between 4.98 and 5.02 cm is 0.682 (68.2%)