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Alex
3 years ago
12

Please answer this very simple and easy attachment I will say what each choose is down below! The chooses have 4 options each ex

cept for the third and, you choose between them and please CORRECTLY!! First Choose, Odd, Even, Rounded, Compatible Second Choose, 30, 36, 40, 35 Third Choose, 10, 7, 6

Mathematics
1 answer:
Bas_tet [7]3 years ago
7 0

Answer:

1st choose: Rounded

2nd Choose: 36

3rd Choose: 6

Step-by-step explanation:

1st  Choose: You want rounded numbers because it makes the problem simpler.

2nd Choose:  35 3/4 rounds to 36.

3rd Choose: 5 7/8 rounds to 6. 36 and 6 divides evenly.

Hopes this helps:)

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25x=2544 what does x represent
Georgia [21]
Hey there! 

Firstly, we are going to divide by 25 on each of your sides because it paired off with a variable

Here's what I meant! 

\frac{25x}{25} =  \frac{2,544}{25}

We would have to cancel out the: \frac{25x}{25} because it gives us 1

Answer: x =  \frac{2,544}{25}

Good luck on your assignment and enjoy your day! 

~LoveYourselfFirst:)

5 0
3 years ago
Alex and Ben shares £520 in the ratio 1:3.<br> What fractions of the £520 does Ben receive?
Arisa [49]
Ben would receive £390 while Alex would only receive £130
4 0
3 years ago
Find the slope of the line
alekssr [168]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
Find the amount of time. <br> 8. I = $2000, P = $5000, r = 8%
algol [13]

Answer:

t = 5 years

Step-by-step explanation:

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P = $ 5000

r = 8%

I = P * \frac{r}{100}*t\\\\t =\frac{ I * 100}{P*r}\\\\t =\frac{2000*100}{5000*8}\\\\ = 5

5 0
3 years ago
Show work and explain with formulas:
Marina86 [1]

17 Answer:  205

<u>Step-by-step explanation:</u>

\{1\dfrac{2}{3}+1\dfrac{5}{6}+2+...+8\dfrac{1}{3}\}\implies a_1=1\dfrac{2}{3},\ d=\dfrac{1}{6}\\\\\\a_n=a_1+d(n-1)\qquad solve\ for\ n\\\\8\dfrac{1}{3}=1\dfrac{2}{3}+\dfrac{1}{6}(n-1)\\\\\\\dfrac{25}{3}=\dfrac{5}{3}+\dfrac{1}{6}n-\dfrac{1}{6}\\\\\\\dfrac{50}{6}=\dfrac{10}{6}+\dfrac{1}{6}n-\dfrac{1}{6}\\\\\\\dfrac{41}{6}=\dfrac{1}{6}n\\\\\\\dfrac{41}{6}\cdot 6=n\\\\41=n

\text{Now use the sum formula:}\\\\S_n=\dfrac{a_1+a_n}{2}\cdot n\\\\\\S_{41}=\dfrac{1\dfrac{2}{3}+8\dfrac{1}{3}}{2}\cdot 41\\\\\\.\quad =\dfrac{10}{2}\cdot 41\\\\\\.\quad =5\cdot 41\\\\.\quad =\large\boxed{205}

18 Answer:  1968

<u>Step-by-step explanation:</u>

a_1=-6,\ d=2,\ n=48, \quad \text{solve for }a_{48}\\\\a_{n}=a_1+d(n-1)\\\\a_{48}=-6+2(48-1)\\\\.\quad =-6+2(47)\\\\.\quad =-6+94\\\\.\quad =88

\text{Now use the sum formula:}\\\\S_n=\dfrac{a_1+a_n}{2}\cdot n\\\\\\S_{48}=\dfrac{-6+88}{2}\cdot 48\\\\\\.\quad =\dfrac{82}{2}\cdot 48\\\\\\.\quad =41\cdot 48\\\\.\quad =\large\boxed{1968}

19 Answer:  -116

<u>Step-by-step explanation:</u>

\{3, -2, -7, ...\}\\a_1=3,\ d=-5,\ n=8, \quad \text{solve for }a_{8}\\\\a_{n}=a_1+d(n-1)\\\\a_{8}=3-5(8-1)\\\\.\quad =3-5(7)\\\\.\quad =3-35\\\\.\quad =-32\\\\\text{Now use the sum formula:}\\\\S_8=\dfrac{a_1+a_8}{2}\cdot 8\\\\\\S_{8}=\dfrac{3-32}{2}\cdot 8\\\\\\.\quad =\dfrac{-29}{2}\cdot 8\\\\\\.\quad =-29\cdot 4\\\\.\quad =\large\boxed{-116}

6 0
3 years ago
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