Answer:

Step-by-step explanation:
Because
is being multiplied by S, we can divide
from both sides of the equation. This will give us:
÷
But, that looks a bit hectic. Instead of dividing, you can multiply by the reciprocal (which is essentially how to divide fractions). So, instead of
÷
, you get:
×
When multiplying fractions, remember you can just multiply straight across-- numerator x numerator, then denominator x denominator.
By doing that, you get the fraction 
cannot be simplified any more, so S=
is your answer :)
I hope this helps
The question is asking for you to plug in each number in the brackets into x and solve for y, or f(x), g(x), etc. I will do no. 19 as an example:
f(x) = -3x + 1
This problem has the domains -2, -1, and 0. First, we'll start with -2:
f(x) = -3(-2) + 1
f(x) = 6 + 1
f(x) = 7
Now -1:
f(x) = -3(-1) + 1
f(x) = 3 + 1
f(x) = 4
Lastly, 0:
f(x) = -3(0) + 1
f(x) = 0 + 1
f(x) = 1
For question 23, we can use the distance formula, which is ratextime. The domain in this case is time (t). You can set up a function like this: d(t) = 60t
Answer:
-4+-4
Step-by-step explanation:
A+2.4=7.8
a=-5.4
5.4+2.4=7.8
Answer:
Step-by-step explanation:
There is no pair of real numbers that have a total of -4 and a product of 5. The complex numbers (-2+i) and (-2-i) will meet your requirements.
__
If the numbers of interest are 'a' and 'b', they will be zeros of the quadratic whose factored form is ...
(x -a)(x -b) = 0
Expanding that, we find an opportunity to use the given sum and product numbers:
x² -(a+b)x +ab = 0
x² -(-4)x +5 = 0
Rewriting this in vertex form gives ...
(x² +4x +4) +1 = 0
(x +2)² +1 = 0
We can find the values of x by subtracting 1 and taking the square root.
(x +2)² = -1
x +2 = ±√(-1) = ±i
x = -2±i
The two numbers of interest are -2+i and -2-i.