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Degger [83]
3 years ago
5

I need help with this asap. (4x+2)(x+1)=

Mathematics
2 answers:
Delvig [45]3 years ago
7 0

Answer:

4x² + 6x + 2

Step-by-step explanation:

Solve by factoring.

4x · x = 4x²

4x · 1 = 4x

2x · 1 = 2x

2 · 1 = 2

Combine like terms.

4x² + 4x + 2x + 2

= 4x² + 6x + 2

Hope this helps.

telo118 [61]3 years ago
3 0
The answer is 4x^2 + 6x +2
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100 mL=1 L
Multiply the whole equation by 4.
400 mL=4 L

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8 0
4 years ago
Someone please help me answer this
uranmaximum [27]

Answer:

2^10

Step-by-step explanation:

When multipying indices, if the base is the same then just add the indices.

3 0
3 years ago
Help me please and thank you!
lorasvet [3.4K]

Answer:

-4/3

Step-by-step explanation:

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6 0
3 years ago
What is the length of a short leg of a 30-60-90 triangle shown below?
Alekssandra [29.7K]

Answer:

5

Step-by-step explanation:

since 30-60-90 triangles are special right triangles, we know that if the short leg=x, the long leg= xsqrt(3). so the short leg= 5 sqrt(3) /(sqrt(3) = 5

7 0
3 years ago
HII PLEASE HELP ME IN THIS
Rzqust [24]

Step-by-step explanation:

(i) Sum the forces at point M in the x direction.

∑F = ma

-T sin 30° − T sin 30° + 5 N = 0

2T sin 30° = 5 N

T = 5 N

(ii) Sum the forces on the ring in the x direction.

∑F = ma

T sin 30° − N = 0

N = 2.5 N

Sum the forces on the ring in the y direction.

∑F = ma

T cos 30° − mg − Nμ = 0

Nμ = T cos 30° − mg

2.5 μ = 5 cos 30° − 2

μ = 0.932

(iii) Sum the forces on the ring in the y direction.

∑F = ma

T cos 30° − m₁g − m₂g + Nμ = 0

m₂g = T cos 30° − m₁g + Nμ

m (10) = 5 cos 30° − 2 + (2.5)(0.932)

m = 0.466 kg

8 0
3 years ago
Read 2 more answers
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