3 years ago

Solve 64^x = 16^x−1.

2 answers:

7 0

64^x=16^x-1====> Make the bases the same
4^3(x)=4^2(x-1)=> Solve for x by bringing down the exponent without the base.
3(x)=2(x-1)=====> Distribute
3x=2x-2======> Now solve for x
3x = 2x-2
-2x -2x
x=-2
Therefore x is negative two

tresset_1 [31]3 years ago

6 0

Answer:

x = -2

Step-by-step explanation:

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