$distance = \sqrt{x2 - x1 + y2 - y1} \\ here \\ \: \: \: \: x1 = 4 \\ \: \: \: \: x2 = 8 \\ \: \: \: \: y1 = 6 \\ \: \: \: \: y2 = 9 \\ now \: we \: have \: to \: substitute \: the \: given \: values \: in \: the \: above \: formula \\ we \: get \\ \: \: \: \: \: \: = \sqrt{8 - 4 + 9 - 6} \\ \: \: \: \: \: \: = \sqrt{4 + 3} \\ \: \: \: \: \: \: = \sqrt{7} \\ \\ hope \: it \: helped$

4 0

3 years ago

I need help with this question please with an explanation <br> ANSWER ASAP!!!!!!

rjkz [21]

The fish is 2.25 ft above the water surface.

Step-by-step explanation:

Step 1: Given expression for height of the fish above the water surface, y = -16x² + 12x where x is time in seconds. Find height after 0.375 seconds

⇒ y = -16(0.375)² + 12 × 0.375

= -2.25 + 4.5

= 2.25 ft

4 0

3 years ago

Find the quotient, and write it in lowest terms.<br> 3 4/5 ÷ 2 11/15

barxatty [35]

Answer to your problem is:
1 16/41

3 0

4 years ago

H - 4/ j= k for J please help

dimulka [17.4K]

h=k+4/j dude just go this thing called cymath

6 0

3 years ago