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kotegsom [21]
3 years ago
13

Evaluate the function below for x=2.   F(x)=2x^3-x^2-5x+6

Mathematics
2 answers:
Advocard [28]3 years ago
7 0
f(x)=2x^3-x^2-5x+6 \ \ \ \boxed{x=2}\\
\\
f(2)=2*2^3-2^2-5*2+6\\
\\
f(2)=16-4-10+6\\
\\
f(2)=8
Oksanka [162]3 years ago
4 0

Answer:

A Function states an equation that has only one answer for y for every x. Also, a function assigns exactly one output to each input of a specified type.

i,e y= f(x) where x represents the input variable and y represents the output value.

Given the function: F(x) = 2x^3-x^2-5x+6

Substitute the given input value of x =2 , we get;

F(2) = 2(2)^3-(2)^2-5(2)+6

F(2) = 2(8)-4-10+6

or

F(2) = 16-4-10+6

Simplify:

F(2) = 8

Therefore, the function F(x)=2x^3-x^2-5x+6 for x=2, we have F(2) =8.

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