5 consecutive even integers: 2n, 2n+2, 2n+4, 2n+6, 2n+8 for any integer n The sum of the two smallest of five consecutive even integers is 50 less than the sum of the other three integers: 2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 504n + 2 = 6n -3234 = 2nn = 17 <span>The smallest integer in our sequence is 2n = 2*17 = 34</span> Check:2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 5034 + 36 = 38 + 40 + 42 - 5070 = 120 - 5070 = 70
Answer:
Step-by-step explanation:

Answer:
a) 0.1353
b) 0.3679
Step-by-step explanation:
Let's start by defining the random variable T.
T : ''The time (in hours) required to repair a machine''
T ~ exp (λ)
T ~ exp (1)
The probability density function for the exponential distribution is
(In the equation I replaced λ = L)

With L > 0 and x ≥ 0
In this exercise λ = 1 ⇒

For a)





For b)

The event (T ≥ 10 / T > 9) is equivalent to the event T ≥ 1 so they have the same probability of occur



Answer:
there is two solutions to that problem. you can find x is equal to two numbers.
C=2

r
A=

r<span>²
C=2</span>

r=58

2r=58
r=29
A=

r<span>²
A=29</span><span>²</span>

A=841