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olga nikolaevna [1]
3 years ago
6

Write a function rule for the area of a triangle whose base is 4 ft more than the height. What is the area of the triangle when

its height is 6 ft?
Mathematics
1 answer:
solong [7]3 years ago
6 0

Answer:

A) Area as function of H ,

     F'(a) = 2 +H

B) Area of triangle with height 6ft = 30 ft²      

Step-by-step explanation:

Given as for a triangle ,

Let the height of triangle = H ft

And base = 4 ft + H ft

Now area of triangle = \frac{1}{2} × height  × base

                          F (a) =  \frac{1}{2} × H × ( 4ft + H ft)

Or,                      F (a) =  \frac{1}{2} × ( 4H + H² )

Now,   here Area is function of height ,

So ,                    F'(a) = \frac{1}{2}(4 + 2H)

Hence Area as function of H ,

                          F'(a) = 2 +H

Now For height = 6 ft

Area of triangle = \frac{1}{2} × height × base

                          = \frac{1}{2} × H × ( 4ft + H ft)

                          = \frac{1}{2} × ( 4H + H² )

                          =  \frac{1}{2} × ( 24 + 36 )

                          = \frac{1}{2} × ( 60 )

                          = 30 ft²

Hence Area of triangle with height 6ft = 30 ft²      Answer

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Lady_Fox [76]

Answer:

16 males and 9 females

Step-by-step explanation:

To solve this we can use a system of equations.

Let's start by naming the number of females x.

The number of males would then be y.

<u>Using these variables, we can set up 2 equations using info provided:</u>

A french class has a total of 25 students, -> x+y=25

The number of males is 7 more than the number of females -> x+7=y

Use substitution to solve.

<u>From the second equation:</u>

x+7=y

Subtract 7 from both sides.

x=y-7

Substitute that into the first equation.

x+y=25

y-7+y=25

Combine like terms.

2y-7=25

Add 7 to both sides.

2y=32

Divide both sides by 2.

y=16

Substitute y=16 into equation 2.

x+7=y

x+7=16

Subtract 7 from both sides.

x=9

Therefore, there are 16 males and 9 females in the french class.

3 0
2 years ago
Read 2 more answers
Hi, Could anyone help me with my homework
tatiyna

Answer:

\hookrightarrow \sf  x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096

solving steps:

\rightarrow \sf (x + 4)^6

\bold{rewrite \ the \ following}

\rightarrow \sf (x + 4)^2   (x + 4)^2   (x + 4)^2

\bold {formula \ used : \sf  (x+a)^2 = (x^2 + 2xa + a^2)}

\rightarrow \sf (x^2 + 8x+16)    (x^2 + 8x+16)    (x^2 + 8x+16)

\bold{simplify \ by  \ removing \ parenthesis}

\rightarrow \sf (x^4 +8x^3 + 16x^2 + 8x^3 +64x^2 + 128x+16x^2+128x+256 ) (x^2 + 8x+16)

\bold{basic \ addition \ of \ integers }

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\bold{remove \ parenthesis}

\rightarrow \sf (x^6 + 16x^5 + 96x^4 + 256x^3 + 256x^2 + 8x^6 + 128x^4 + 768x^3 + 2048x^2 + 2048 + 16x^4 + 256x^3 + 1536x^2 + 4096x + 4096)

\bold {final \ answer:}

\rightarrow \sf  x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096

8 0
2 years ago
ryan can build 4 desks in one day and larry can build 4 desks in 2 days. if larry starts work one day before ryan, how long will
MissTica
You can make an equation with this information using a variable for the number of days and solve for that variable. Here we can use d to represent days.

Ryan can build 4 desks in a day, so you could express his production as 4d.

Larry can build 4 desks in 2 days, so you could say he makes 2 desks in 1 day, expressed as 2d.

If Larry starts work one day before Ryan, he's made an extra 2 desks. To get 32 desks, you need to add together those 2 desks Larry made, however many desks Larry can make, and however many desks Ryan can make:

2 + 4d + 2d = 32.

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Vadim26 [7]

Answer:

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Step-by-step explanation:

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AfilCa [17]

Given:

Total number of questions = 6

Choice for each question (in MCQ) = 4

Assuming that no questions are left unanswered.

To find:

The total number ways to answer the quiz, assuming that no questions are left unanswered.

Solution:

Here, Number of ways to answer each question = 4

To find the  total number ways to answer 6 MCQ, we have to have to multiply number of ways to answer each question 6 times.

Total number of ways to answer six-question quiz with 4-choice multiple choice questions is

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Therefore, the required number of ways is 4096.

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