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4 years ago

What is 15/10 as a mixed number.

Mathematics

2 answers:

Anarel [89]4 years ago

6 0

Answer:

1 1/2

Step-by-step explanation:

Andre45 [30]4 years ago

6 0

Answer: 15/10 =1.5000=1, 15-(10•1)=5, 1 5/10= 1 1/2

Step-by-step explanation: I found the whole number first to do that I divided 15 by 10 and got 1.5000= 1. Then you will have to find new numerators, and you would have to multiply your first answer by 10 then subtract 15. Then you would put that together and get 1 5/10, lastly you would have to reduce that and get 1 1/2, and that’s the answer.

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The circle graph shows the most important problems for the 15,153,805 high school teenagers in a country. Without using a

solmaris [256]

Answer:

$Number = 1818457$

Step-by-step explanation:

Given

Teenagers = 15,153,805

Doing Well = 12% ---- From the comment on this question

Required

Determine the number of teenagers in this category

To solve this question, we simply multiply the total number of teenagers by the given percentage.

i.e.

$Number = Teenagers * \%Doing\ Well$

$Number = 15,153,805* 12\%$

$Number = 1818456.6$

Approximate

$Number = 1818457$

Hence, there are 1818457 in this category.

NB: None of the options answer this question

6 0

3 years ago

The centers of a 15 kg lead ball and a 130 g lead ball are separated by 6.0 cm.

Elina [12.6K]

F = G $m_{1} m_{2}$ / d^2
G = 6.67*10^-11 Nm^2/kg^2 m_1 = 15kg m_2 = 130g = .13kg d = 6cm = 0.06m

F = 6.67*10^-11 * ((15*.13)/.06)
F = 2.16775 $*10^{-11}$

5 0

3 years ago

Read 2 more answers

(2xy+y) divided (2xy+4, if x=+6,Y-3 Help someone

Natali [406]

What you do is plug the numbers for each variable ur equation will look like 2(6)(-3)+4
lets solve it step by step 2(6)(-3)+4
12(-3)+4 then -36+4 and ur answer will be -32

8 0

3 years ago

Find dy/dx for 4 - xy = y^3

storchak [24]

Answer:

$\frac{dy}{dx}=-\frac{y}{3y^2+x}$

Step-by-step explanation:

4-xy=y^3

dy/dx=?

$\frac{d(4-xy)}{dx}=\frac{d(y^3)}{dx}\\ \frac{d(4)}{dx}-\frac{d(xy)}{dx}=3y^{3-1}\frac{dy}{dx}\\ 0-(\frac{dx}{dx}y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -(1y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -(y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -y-x\frac{dy}{dx}=3y^2\frac{dy}{dx}$