All categories

2 years ago

What is the slope of the line x = 3?

Mathematics

1 answer:

babymother [125]2 years ago

4 0

Answer:

Since x=−3 is a vertical line, the slope is undefined.

Step-by-step explanation:

You might be interested in

Which problem could be solved using this equation? 12x + 3 = 39

boyakko [2]

The answer is the first one , A

7 0

2 years ago

Read 2 more answers

Please help me with this

kirill [66]

Answer:

15/2 or 7.5

Step-by-step explanation:

$5/6 (x + 1/2 + 4)$

distribute 5/6 to each number

$5/6x + 5/12 + 10/3$

change the fraction 10/3 so that it will have the same denominator as 5/12

$\frac{10}{3} *4$ = 40/12

$5/6x + 5/12 + 40/12\\5/6x + 45/12$

divide both sides by 5/6

$x = 9/2$

$5/6*9/2+5/12+10/3 = \frac{15}{2}$

3 0

1 year ago

The sum of the digits of a certain two-digit number is 13. Reversing its digits decreases the number by 45. Find the number..

lesya [120]

Answer:

......................

5 0

2 years ago

A rectangular prism must have a base with an area of no more than 27 square meters. The width of the base must be 9 meters less

NISA [10]

Answer:

you can get a good night's sleep and I will talk to you later I love you too baby girl and I Will always Love you xoxoxo I love you

5 0

1 year ago

4)In order to set rates, an insurance company is trying to estimate the number of sick daysthat full time workers at an auto rep

bagirrra123 [75]

Answer:

A sample of 18 is required.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.92}{2} = 0.04$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.04 = 0.96$ , so Z = 1.88.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

A previous study indicated that the standard deviation was 2.2 days.

This means that $\sigma = 2.2$

How large a sample must be selected if the company wants to be 92% confident that the true mean differs from the sample mean by no more than 1 day?

This is n for which M = 1. So

$M = z\frac{\sigma}{\sqrt{n}}$

$1 = 1.88\frac{2.2}{\sqrt{n}}$

$\sqrt{n} = 1.88*2.2$

$(\sqrt{n})^2 = (1.88*2.2)^2$

$n = 17.1$

Rounding up:

A sample of 18 is required.

3 0

2 years ago