Question

If f(x) = 2x + 7 and g(x) = x2 2, what is [f o g](3)?

Answer 1

Answer:

The value [fog](3) is 29.

Step-by-step explanation:

The given functions are

$f(x)=2x+7$

$g(x)=x^2+2$

We have to find [fog](3).

$(f\circ g)(x)=f(g(x))$

$(f\circ g)(3)=f(g(3))$

$(f\circ g)(3)=f(3^2+2)$              $[\because g(x)=x^2+2]$

$(f\circ g)(3)=f(11)$

$(f\circ g)(3)=2(11)+7$              $[\because f(x)=2x+7]$

$(f\circ g)(3)=22+7$

$(f\circ g)(3)=29$

Therefore the value [fog](3) is 29.

Answer 2

Hmm is your question correct I am a bit confused on the x2 2