A+b = c+d
a+b = 770/2 ( a+b+c+d = 770)
a+b = 385
c+d = 385
a+b+a-b = 385+49
2a = 434
a = 434/2
a = 217
a-b=49
217-49= b
b = 168
c+d+c-d = 385+211
2c = 596
c = 596/2
c = 298
c-d = 211
c-211= d
298-211 = d
d = 87
Therefore, a=217, b=168, c=298, d=87
I dont understand can u put the question in full form
X represents the ideal weight of the dog. The first equation is correct because the ideal weight increased by seven pounds equals 44, since he currently weighs 44 pounds and must decrease that by 7 to get the ideal weight. The second one is also correct because 44 minus the ideal weight is seven, since seven is given as the difference between 44 and the ideal weight.
Another equation would be x=44-7. This is because the ideal weight is 44 pounds minus the seven pounds the dog loses.
Answer:
True
Step-by-step explanation:
Suppose that:
n = fg
here, we can say n, f, and g are positive integers.
the above statement can be read as n is a function of f and g (i.e f and g are factors of n)
Making g the subject of the formula, then:
here, g is said to be the factor of n, since
We conclude that this statement is true.
Answer: 2.36
Step-by-step explanation:
Using the μ=∑[x⋅P(X=x)
U will need to do
2/11 because you have 2 labeled 1
3/11 because you have 3 labeled 2
6/11 because you have 6 labeled 3
Then you will do:
1 x 2/11 = 0.18
2 x 3/11 = 0.5454 = 0.55
3 x 6/11 = 1.63
Then add them all together to find the μ
0.18 + 0.55 + 1.63 = 2.36
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