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3 years ago

13

If I were to solve for x and there is x to the third power equals to 64. What would be my answer?

1 answer:

viva [34]3 years ago

6 0

Answer:

x=4

Step-by-step explanation:

if you do $\sqrt[3]{64}$ you'll get that $4^{3}$ is 64.

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Find the measure of the are or angle indicated. Assume that lines which appear tanget are tangents.

Brilliant_brown [7]

9514 1404 393

Answer:

85°
60°

Step-by-step explanation:

1. Angle JKL is half the measure of the intercepted arc JK.

(1/2)JK = 1/2(360° -190°) = (1/2)(170°) = 85°

angle JKL is 85°

__

2. The angle between tangents is the supplement of the intercepted arc.

angle JKL = 180° -(360° -240°)

angle JKL = 60°

8 0

2 years ago

Solve 3x−5 = 9. Not sure what to do

choli [55]

Answer:

x= 14/3

That's the answer :)

3 0

3 years ago

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Can someone help me with this problem?

Diano4ka-milaya [45]

Can you show the answer choices but I believe is 18

3 0

2 years ago

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Ruth wants to purchase a new video game that costs $59.00 and several bags of chips that sell for $1.99 each. She can spend no m

allsm [11]

Answer:

1.99c + 59 ≥ 75, where c ≥ 8.04

Step-by-step explanation:

8 0

2 years ago

Which choice is equivalent to the product below when x>0?

V125BC [204]

Answer:

D

Step-by-step explanation:

Using the rule of radicals

$\sqrt{\frac{a}{b} }$ = $\frac{\sqrt{a} }{\sqrt{b} }$

$\sqrt{a\\}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

Given

$\sqrt{\frac{6}{x} }$ × $\sqrt{\frac{x^2}{24} }$

= $\frac{\sqrt{6} }{\sqrt{x} }$ × $\frac{x^2}{24}$

= $\frac{\sqrt{6} }{\sqrt{x} }$ × $\frac{x}{2 \sqrt{6\\} }$

Cancel $\sqrt{6}$ on numerator/ denominator

= $\frac{1}{\sqrt{x} }$ × $\frac{x}{2\\}$

= $\frac{1}{\sqrt{x} }$ × $\frac{(\sqrt{x})^2 }{2}$

Cancel $\sqrt{x}$ on numerator/ denominator, leaving

= $\frac{\sqrt{x} }{2}$ → D

4 0

3 years ago