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Maurinko [17]
3 years ago
13

If I were to solve for x and there is x to the third power equals to 64. What would be my answer?

Mathematics
1 answer:
viva [34]3 years ago
6 0

Answer:

x=4

Step-by-step explanation:

if you do \sqrt[3]{64} you'll get that 4^{3} is 64.

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Q8
IRINA_888 [86]

Answer:

Ethan

Question b is incomplete

Step-by-step explanation:

Given the masses of the 6 insects below :

Name of Insect ______ Mass (m)

Arthur _____________ 7.8259

Bethan ____________ 7.2659

Clarry ______________8.159

Deena _____________ 7.4559

Ethan ______________ 8.9459

Freya ______________ 7.0159

Write the name of the stick insect with m > 8.85g

Mass (m) greater than 8.55 g

From the table :

8.945 > 8.55 ;

Hence, Ethan

(b) Write the name of the stick insect with m s 7.155 g

Question b isn't complete

7 0
3 years ago
1. X= 2- y<br> X + 3y = 56
just olya [345]

Answer:

(-25,27)

Step-by-step explanation:

5 0
3 years ago
Students at Salt Lake Community College pay 1.667 * 104 dollars for tuition.Students at George Washington University pay 5.5011
podryga [215]

Answer:

its rigged 1234

Step-by-step explanation:

(2)23x235

5 0
3 years ago
Boyle’s law states that for a fixed amount of gas, the volume of the gas at a constant temperature is inversely proportional to
IgorC [24]

Answer:

41 cm

Step-by-step explanation:

v= a/p

v= 9.84 when p= 50

9.84= a/50        a=492

v= 492/p

12= 492/p

p= 492/12

p= 41

4 0
3 years ago
0.1.13
Brilliant_brown [7]

Answer:

Distance = 1572\ feet

Step-by-step explanation:

Given

Courthouse = 1068 feet

<em>Gallery = 0.5 mile ----- Missing Part of Question</em>

<em />

What the question implies is to

determine the distance between these two locations

This is done as follows:

Distance = |Courthouse - Gallery|

Substitute values for Courthouse and Gallery

Distance = |1068\ feet - 0.5\ mile|

Convert 0.5 mile to feet (1 mile = 5280 feet)

Distance = |1068\ feet - 0.5 * 5280\ feet|

Distance = |1068\ feet - 2640\ feet|

Distance = |-1572\ feet|

Distance = 1572\ feet

<em>Hence, the required distance is 1572 feet</em>

3 0
3 years ago
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