All categories

2 years ago

There are 120 people in a sport centre.

Mathematics

1 answer:

Phantasy [73]2 years ago

7 0

Answer:

62%

Step-by-step explanation:

120-46=74

74/120 don't use

simplify 37/60

to percent; 62%

You might be interested in

If Vector u=(5,-7) and v=(-11,3), 2v-6u=_____ and ||2v-6u||≈_____

victus00 [196]

Part 1: Correct.

Part 2

$\sqrt{(-52)^2 + 48^2} \approx 70.77$

8 0

1 year ago

what is the area of a circle with radius of 7cm using 3.14 for pi and round to he nearest tenth plz hurry

Sophie [7]

Answer:153.9 cm

Step-by-step explanation:

The area of a circle is found by pi × radius squared and pi is aprox 3.14 so 3.15×7² = 153.86 then round off to the nearest tenth you get 153.9

5 0

3 years ago

Read 2 more answers

HELP I SUCK AT MATH!!!!AND IM FAILING STILL!!!!!

alukav5142 [94]

Answer:

y=x+1

Step-by-step explanation:

The slop and y-int are 1, just like on the graph

8 0

2 years ago

Read 2 more answers

Write the integer from least to greatest. 4, 12, -12, -11

maxonik [38]

Answer:

-12, -11, 4, 12

Step-by-step explanation:

A negative number is less the higher it is, and a positive number is more the higher it is

3 0

2 years ago

Pleasee help ASAP!! No links pleaseee!!!

Ilya [14]

Given:

The vertices of the rectangle ABCD are A(0,1), B(2,4), C(6,0), D(4,-3).

To find:

The area of the rectangle.

Solution:

Distance formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using the distance formula, we get

$AB=\sqrt{(2-0)^2+(4-1)^2}$

$AB=\sqrt{(2)^2+(3)^2}$

$AB=\sqrt{4+9}$

$AB=\sqrt{13}$

Similarly,

$BC=\sqrt{(6-2)^2+(0-4)^2}$

$BC=\sqrt{(4)^2+(-4)^2}$

$BC=\sqrt{16+16}$

$BC=\sqrt{32}$

$BC=4\sqrt{2}$

Now, the length of the rectangle is $AB=\sqrt{13}$ and the width of the rectangle is $BC=4\sqrt{2}$ . So, the area of the rectangle is:

$A=length \times width$

$A=\sqrt{13}\times 4\sqrt{2}$

$A=4\sqrt{26}$

$A\approx 20$

Therefore, the area of the rectangle is 20 square units.

3 0

2 years ago