If you reflect a point from quadrant IV over the x axis, where will the new point be located. *
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<h3>x²-4=x+2</h3><h3>=>x²-x-4-2=0</h3><h3>=>x²-x-6=0</h3><h3>=>x²-3x+2x-6=0</h3><h3>=>x(x-3)+2(x-3)=0</h3><h3>=>(x-3)(x+2)=0</h3><h3>=>x=3 and x= -2</h3><h2>iz the correct answer!</h2>✌️✌️
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