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Inessa05 [86]
2 years ago
11

How many solutions ? ( 1 solution , no solution , infinite solutions ) I WILL MAKE U BRAINLIST NEED ASAP

Mathematics
2 answers:
Ivanshal [37]2 years ago
6 0
There are more than one solutions that are solvable in these equations!
Mila [183]2 years ago
5 0

Answer:

one solution

Step-by-step explanation:

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What are the zeroes of f(x) = x2 + 5x + 6?
photoshop1234 [79]
Here is your answer

a) x=-2, -3

REASON :
f(x)= {x}^{2}+5x+6

= {x}^{2}+2x+3x+6

= x(x+2)+3(x+2)

= (x+2)(x+3)

To find zeroes

f(x)= 0

So,

(x+2)(x+3)=0

x=-2 or x=-3

HOPE IT IS USEFUL
5 0
3 years ago
Read 2 more answers
What are the first 5 terms of an arithmetic sequence with a common difference of – 0.4 and the first term of 0.7?
vovikov84 [41]
A no is the correct ans .
5 0
3 years ago
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a survey of a random sample of 1280 student loan borrowers found that 218 had loans totaling more than $40,000 for their undergr
AnnyKZ [126]

Answer:

1/10 or 0.1

Step-by-step explanation:218/1280 (40,000 is just a number to knock you off)

3 0
3 years ago
If 10 oranges cost 2.00 and 8 oranges cost 1.20 which is the better deal
s344n2d4d5 [400]

Answer:

10 oranges

Step-by-step explanation:

7 0
3 years ago
If AC=5cm, BC=12cm, and m AC= 40 degrees what is the radius of the circumscribed circle
melamori03 [73]
Let's assume they meant C=40 degrees.  With an angle like that they're asking for approximation; we'll oblige.

The circumradius is the product of the triangle sides divided by four times the area.

Here we have remaining side given by the Law of Cosines.

AB^2 = AC^2 + BC^2 - 2\ AC \ BC \cos C

AB^2 = AC^2 + BC^2  - 2 AC \ AB \cos C = 5^2 + 12^2 - 2(5)(12) \cos 40^\circ

AB = \sqrt{  169 - 120 \cos 40 ^\circ}  \approx 8.77921789

The area is \frac 1 2\ AC \ BC \sin C = \frac 1 2 (5)(12) \sin 40^\circ \approx 19.283628



The circumradius is  r \approx \dfrac{(5)(12)(8.77921789 )}{ 4 (19.283628) }  = 6.829019329




5 0
3 years ago
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