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3 years ago

Round number to nearest hundred 1,427 as 1,420. 68,136 as 68,130. 271,308 as 271,300. 7,593,656 as 7,594,000 right?

1 answer:

3 0

Normally to round a number to the nearest hundred you want to go to the hundreds column for example:
1427
1...thousand, 4...hundred, 2...tenth, and 7... ones so this one would be 1400
68136=68100 and so on.... hope this helps

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A Toffee costs 15% more than a mint costs & 80. What is the price of a Toffee

Anestetic [448]

Answer:

the price of Toffee is 92

Step-by-step explanation:

first we have to find 15% of 80 which is

15/100 × 80= 12 than we add it with 80 because the toffee is 15% more than a mint and therefore we get 80+12=92

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2 years ago

Let u be an angle in the 4th quadrant with cos u=8/9<br><br> Then sin u=

lutik1710 [3]

To solve for the last side of the triangle, use the Pythagorean Theorem:
(8)^2 + x^2 = (9)^2
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However, this is a NEGATIVE sqrt 17 because the terminal side is in quadrant 4, meaning that this side is under the X-axis and therefore negative.
Now that you know the side opposite of u in the triangle, do opposite/hypotenuse.
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3 years ago

Please don’t only answer this explain how to figure it out so I have it for future reference

Deffense [45]

The polygon is built of 7 triangles (picture).

$P=7\cdot\dfrac{1}{2}ah\\
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h=30 \text{ m}\\\\
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3 years ago

Finding angle measures between intersecting lines

grin007 [14]

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3 years ago

A bag contains five white balls and five black balls. Your goal is to draw two black balls.

umka21 [38]

Answer:

a.) the probability that both the ball drawn are black = $\frac{10}{45} = \frac{2}{9}$

b.) Sum of all the probabilities = $\frac{\frac{2}{9} }{1 - \frac{2}{9} } = \frac{\frac{2}{9} }{\frac{8}{9} } = \frac{2}{8} =\frac{1}{4} = 0.25$

Step-by-step explanation:

a) two balls are drawn at random .

total number of balls = 10

number of black balls = 5

number of white balls = 5.

the number of ways two balls can be drawn = $\binom{10}{2} = \frac{10!}{2! 8!} = \frac{10\times9}{2} = 45$

the number of ways two black balls can be drawn = $\binom{5}{2} = \frac{5!}{2! 3!} = \frac{5\times4}{2} = 10$

the probability that both the ball drawn are black = $\frac{10}{45} = \frac{2}{9}$

b) probability that First draw of two black balls = $\frac{2}{9}$

probability that first draw is of two white balls is and second draw is of

two black balls = $\frac{2}{9} \times\frac{2}{9}$

Probability that first two draws are of white balls and the third draw is of

two black balls = $\frac{2}{9} \times\frac{2}{9} \times\frac{2}{9}$

This is a geometric sequence and the final probability will be the sum of

all such probabilities, where we can take the the sequence to be an infinite series and the first term is $\frac{2}{9}$ and the common ratio is $\frac{2}{9}$ which is less than 1.

Sum of all the probabilities = $\frac{\frac{2}{9} }{1 - \frac{2}{9} } = \frac{\frac{2}{9} }{\frac{8}{9} } = \frac{2}{8} =\frac{1}{4} = 0.25$

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3 years ago