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scZoUnD [109]
3 years ago
8

HELP Solve for the following equation showing all work step by step. 3646 = 1+5(4r+17)^3/2

Mathematics
1 answer:
morpeh [17]3 years ago
8 0

3646 = 1 + 5(4 + 17)32

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Which expression is equivalent to 6^2 times 6^6?<br> a. 6^8<br> b. (6^3)^5<br> c. 6^12<br> d. 6^8/6
ratelena [41]

Step-by-step explanation:

<u>Rule:</u>

When exponents multiply, they're adding.

<u>Multiply:</u>

{6}^{2}  \times  {6}^{6}  =  {6}^{2 + 6}  =  {6}^{8}

Option A is correct.

8 0
2 years ago
Wes bought a conference table for $960. what is it worth after depreciating at a rate of 12% per year for 4 years?
murzikaleks [220]

Answer:

$594.03

Step-by-step explanation:

Using the exponential function;

A = Pe^-rt

Principal = $960

Rate r = 12% = 0.12

Time t = 4years

Substitute

A = 960e^-(0.12*)*4

A = 960e^-0.48

A = 960(0.61878)

A = 594.03

HEnce the worth after 4years will be $594.03

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3 years ago
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sleet_krkn [62]

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3 0
3 years ago
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Julian is 10 years younger than Thomas. The sum of their age is 40. What is Thomas age
Karolina [17]

So first we subtract 10 from 40 and get 30. We divide this by the number of people (2) to get Julian's age: 15. We add 10 to this to get Thomas age = 25. 25 + 15 = 40

Thomas is 25 years old.

3 0
3 years ago
Use Green's Theorem to evaluate F · dr. C (Check the orientation of the curve before applying the theorem.)F(x, y) = y cos(x) −
Sergeeva-Olga [200]

Notice that <em>C</em> has a clockwise orientation. By Green's theorem, we have

\displaystyle\int_C\mathbf F(x,y)\cdot\mathrm d\mathbf r=-\iint_D\left(\frac{\partial(xy+x\cos x)}{\partial x}-\frac{\partial(y\cos x-xy)}{\partial y}\right)\,\mathrm dx\,\mathrm dy

where <em>D</em> is the triangule region with <em>C</em> as its boundary, given by the set

D=\{(x,y)\mid0\le x\le2\land0\le y\le8-4x\}

So we have

\displaystyle\int_C\mathbf F(x,y)\cdot\mathrm d\mathbf r=-\int_0^2\int_0^{8-4x}((y+\cos x-x\sin x)-(\cos x-x\sin x))\,\mathrm dy\,\mathrm dx

\displaystyle\int_C\mathbf F(x,y)\cdot\mathrm d\mathbf r=-\int_0^2\int_0^{8-4x}y\,\mathrm dy\,\mathrm dx=\boxed{-\dfrac{64}3}

5 0
3 years ago
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