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3 years ago

Plz help me with dis

Mathematics

2 answers:

Ksivusya [100]3 years ago

8 0

Answer:

1. 1,2,4,8,41,82,164,328

2. 2 and 41

Step-by-step explanation:

the factor is something times it self that equals 328

1 times 328

2 times 164

3 times 109.33

4 times 82

and such on

YOU DON'T WANT DECIMALS SO 3 WON'T WORK

and you keep going till you have all the factors

for number 2

prime numbers are numbers that are only dividable by 1 and itself

2 times 1

41 times 1

are the only numbers that go in to 2 and 1, 41 and 1

once you find all the primes in your factors your done for this problem the primes are 2 and 41

jeka57 [31]3 years ago

7 0

Answer:

1) factor pairs- 1*328, 2*164, 4*82, 8*41

1,2,4,8,41,82,164,328

2) 2^3, 41

not a prime number

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Answer:

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Step-by-step explanation:

Akira receives the prize at the science fair for having the most informative project her trophy is in the shape of a square pyramid and is covered in shiny gold foil how much gold foil did it take to cover the trophy including the bottom

Total surface = surface area of the base square + area of 4 triangles

Calculate the surface area of the base square

surface area of the square = s^2

where s= side length

s=3 in

The surface area of the base =s^2

=3^2

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The surface area of the side triangles

The area of the triangle = (1/2)* side length* slant height

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Therefore,

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6 0

3 years ago

Please help ASAP!

Kruka [31]

First, recall that

$\sin(-\theta)=-\sin\theta$

So if $\sin(-\theta)=\dfrac15$ , then $\sin\theta=-\dfrac15$ .

Second,

$\tan\theta=\dfrac{\sin\theta}{\cos\theta}$

We know that $\tan\theta>0$ and $\sin\theta$ , which means we should also have $\cos\theta$ .

Third,

$\sin^2\theta+\cos^2\theta=1\implies\cos\theta=\pm\sqrt{1-\sin^2\theta}$

but as we've already shown, we need to have $\cos\theta$ , so we pick the negative root.

Finally,

$\tan\theta=\dfrac{\sin\theta}{\cos\theta}\iff\dfrac6{\sqrt{12}}=\dfrac{-\frac15}{\cos\theta}\implies\cos\theta=-\dfrac1{5\sqrt3}$

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Lemur [1.5K]

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