Angles XQL and MQR are congruent because they are vertical angles. So
209 - 13 <em>b</em> = 146 - 4 <em>b</em>
Solve for <em>b</em> :
209 - 13 <em>b</em> = 146 - 4 <em>b</em>
209 - 146 = 13 <em>b</em> - 4<em> b</em>
63 = 9 <em>b</em>
<em>b</em> = 63/9 = 7
Then the measure of angle XQL is
(209 - 13*7)º = 118º
Answer:
F
Step-by-step explanation:
Y - 0.32y = (1 - 0.32)y = 0.68y
<span>To minimize the perimeter you should always have a square.
sqrt(289) = 17
The dimensions should be 17 X 17
To see , try starting at length 1, and gradually increase the length.
The height decreases at a faster rate than the length increases, up until you reach a square.
Or if you want to use algebra, Say the width is 17-x
Then the length is 289/(17-x)
Now, this is bigger than 17+x, as shown here:
289/(17-x) > 17+x
289 > 289 - x^2
which is true.
so the perimeter would be bigger than 2 * (17- x + 17 + x) = 2 * (2 * 17) = 4 * 17
Again, the dimensions should be a square. 17 X 17.</span>
The outer exponent is 4 so there will be 5 terms all together. By rules of exponents
C(4,0)(3^4)(2^0)(x^8)(y^0) + C(4,1)(3^3)(2^1)(x^6)(y^3) + C(4,2)(3^2)(2^2)(x^4)(y^6) + C(4,3)(3^1)(2^3)(x^2)(y^9) + C(4,4)(3^0)(2^4)(x^0)(y^12)
The coefficient of the 3rd term: C(4,2)(3^2)(2^2) = 6 x 9 x 4 = 216
