How do you find the slope of y=-4/3x - 1?

2 answers:

8 0

I can't think of what the form is called, but the slope is in that equation.

y=mx+b

m is the slope and in that equation, m=-4/3

Bad White [126]3 years ago

6 0

$y= \frac{-4}{3} x-1$
slope intercept form: y=mx+b
y=y
$\frac{-4}{3}x$ =mx
-1=b
mx=slope
slope= $\frac{-4}{3}$ x

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Please answer what the answer for ? Is.

vitfil [10]

Answer:

5/8

Step-by-step explanation:

A. 2/3 × 4/5 × m = 1/3 B. 4/5 × 2/3 × m = 1/3

8/15 × m = 1/3 8/ 15 × m = 1/3

m = 1/3 ÷ 8/15 m = 1/3 ÷ 8/15

m = 1/3 ×15/8 m = 1/3 × 15/8

m = 5/8 m = 5/8

C. 2/3 × 4/5 = 1/3 ÷ m

8/15 = 1/3 × 1/m

8/15 = 1/3m cross multiply

(3m) × (8) = 15

24m = 15

m = 15/24

m= 5/8

4 0

3 years ago

CALC BC HELPPP!!!??? 100PTS!!!

lyudmila [28]

the assumption being that "x" is a plain variable whilst "y" is a function, that matters because the chain rule would be needed for a function, not so for a plain variable.

$4x^2+4x+xy=5\implies 8x+4+\stackrel{\textit{product rule}}{\left( 1\cdot y+x\cdot \cfrac{dy}{dx} \right)}=0 \\\\\\ x\cfrac{dy}{dx}=-8x-4-y\implies \cfrac{dy}{dx}=\cfrac{-8x-4-y}{x}$

now, we know that y(5) = -23, which is another way of saying that when x = 5, y = -23, but we already knew that, we can get that by simply plugging it into the equation hmmm y'(5), well

$\left. \cfrac{dy}{dx}=\cfrac{-8x-4-y}{x} \right|_{\stackrel{x=5~}{\textit{\tiny y=-23}}}\implies \cfrac{-8(5)-4-(-23)}{5}\implies \cfrac{-21}{5}$