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lora16 [44]
3 years ago
11

ALGEBRA 1 ASSIGNMENT QUESTIONS

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
7 0
1. 81 1/2 = 163/2
2. 32 1/5 - 64 1/3 =
   483/15 - 965/15 =
    -482/15 or -32 2/15
3. 16 1/4 = 65/4
4. 49 1/2 + 27 1/3 =
    99/2 + 82/3 =
    297/6 + 164/6 =
    461/6 or 76 5/6
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which of the following is q point slope equation of a line that passes through the point (5,2)and (-1,-6)
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Answer:y - y1 = m(x + x1)

m = (y2 - y1)/(x2 - x1) = (-6 - 2)/(-1 - 5) = -8/(-6) = 4/3

y - 2 = 4/3(x - 5) is a possible answer

y + 6 = 4/3(x + 1) is also a possible answer

Step-by-step explanation:

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Write the equation in standard form for the circle with center (0, – 10) and radius 6.
Artemon [7]

Answer:

Equation of circle in standard form with centre (0, – 10) and radius 6. \mathbf{x^2+(y+10)^2=36}

Step-by-step explanation:

We need to write equation of circle in standard form with centre (0, – 10) and radius 6.

The equation of circle is: (x-h)^2+(y-k)^2=r^2

where (h,k) is centre of circle and r is radius

We are given centre (0,-10) so, h=0, k=-10 and radius r = 6

Putting values and finding equation:

(x-h)^2+(y-k)^2=r^2\\(x-0)^2+(y-(-10))^2=(6)^2\\x^2+(y+10)^2=36

So, equation of circle in standard form with centre (0, – 10) and radius 6. \mathbf{x^2+(y+10)^2=36}

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Step-by-step explanation:

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