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Verizon [17]
3 years ago
14

I must solve for y: x=1/3yz

Mathematics
1 answer:
7nadin3 [17]3 years ago
6 0
X = 1/3 yz
3x = yz
y = 3x/z
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How to solve 9x^2+9x+2
Oksana_A [137]

Answer:

factoring: ( 3 x + 1 ) ( 3 x+ 2 )

expressing/equation: 9x²= 81x

81x + 9x + 2=

9x+81x=90x

90x + 2

Step-by-step explanation:

7 0
3 years ago
What is the equation of a circle whose center is at (-2, 1) and radius is 2.2?
Lena [83]
C is the correct answer
3 0
3 years ago
Combine the following expressions:
melisa1 [442]

ANSWER

(4n - 1)\sqrt{3 n} + 3\sqrt{n}

EXPLANATION

The given expression is

\sqrt{48 {n}^{3} }  +  \sqrt{9n}  -  \sqrt{3n}

We remove the perfect squares under the radical sign.

\sqrt{16 {n}^{2}  \times3 n}  +  \sqrt{9n}  -  \sqrt{3n}

We can now take square root of the perfect squares and simplify them further.

\sqrt{16 {n}^{2}}   \times \sqrt{3 n} +   \sqrt{9} \times  \sqrt{n}  -  \sqrt{3n}

This simplifies to:

4n\sqrt{3 n} + 3\sqrt{n}  -  \sqrt{3n}

This further simplifies to:

(4n - 1)\sqrt{3 n} + 3\sqrt{n}

3 0
3 years ago
Read 2 more answers
The length of a rectangle is 6 yd more than twice the width x. The area is 416 yd2. Find the dimensions of the rectangle.
kati45 [8]

Answer:

13 yds * 32 yds

Step-by-step explanation:

A=area, l=length, w=width

A=w*l

l=6+2w

A=w*(6+2w)

A=6w+2w^2

416=6w+2w^2

416/2=(6w+2w^2)/2

208=3w+w^2

208-208=3w+w^2-208

w^2+3w-208=0

w^2+16w-13w-208=0

w(w+16)-13(w+16)=0

(w-13)(w+16)=0 ==> w+16=0 ==> w=-16, w can't be negative.

w-13=0

<u>w=13</u>

l=6+2w

l=6+2(13)

l=6+26

<u>l=32</u>

Dimensions: 13 * 32

8 0
1 year ago
How would I solve for this ?
Daniel [21]
Multiply the length and width for a rectangle like the one shown.
5.3(2.6) = 13.78 square yards.
3 0
3 years ago
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