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Naddika [18.5K]
3 years ago
9

What is StartFraction 8 Over 9 EndFraction divided by two-thirds? A fraction bar labeled 1. Under the 1 are 9 boxes containing o

ne-ninth. Under the 9 boxes are 3 boxes containing one-third. 1 and one-sixth 1 and StartFraction 2 Over 9 EndFraction 1 and one-third 1 and two-thirds
Mathematics
2 answers:
s344n2d4d5 [400]3 years ago
5 0

Answer:

The correct answer is 1 and 1/3

Step-by-step explanation:

I know this because i took the quiz on edge 2020 in dec

marshall27 [118]3 years ago
4 0

Answer:

C 1 1/3 I got it right in the quiz

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Jenny walked 2.5 miles in 50 minutes . At this rate , how many minutes did it take her to walk 1 mile ?
Harlamova29_29 [7]
For this question, let's use algebra!

<u>2.5 miles</u>  =  <u>50 minutes</u>
 1 mile             x minutes

x minutes = 50 x 1 ÷ 2.5
x minutes = 20

Hope this helps!
8 0
3 years ago
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Recipe A calls for 2 cups of sugar and makes 48 cookies. Recipe B calls for 3 cups of sugar and makes 54 of the same
Serga [27]

Answer:

B has more sugar per cookie

4 0
2 years ago
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A physicist examines 25 water samples for nitrate concentration. The mean nitrate concentration for the sample data is 0.165 cc/
xz_007 [3.2K]

Answer:

The 80% confidence interval for the the population mean nitrate concentration is (0.144, 0.186).

Critical value t=1.318

Step-by-step explanation:

We have to calculate a 80% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=0.165.

The sample size is N=25.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

s_M=\dfrac{s}{\sqrt{N}}=\dfrac{0.078}{\sqrt{25}}=\dfrac{0.078}{5}=0.016

The degrees of freedom for this sample size are:

df=n-1=25-1=24

The t-value for a 80% confidence interval and 24 degrees of freedom is t=1.318.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=1.318 \cdot 0.016=0.021

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 0.165-0.021=0.144\\\\UL=M+t \cdot s_M = 0.165+0.021=0.186

The 80% confidence interval for the population mean nitrate concentration is (0.144, 0.186).

6 0
3 years ago
(I NEED THIS ASAP) Find the slope of the line. Use points shown, (-1,-5) and(2,1)
patriot [66]

Answer:

2/1 or 2

Step-by-step explanation:

You go up 6 and over 3 simplify 6/3 to 2/1=2

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2 years ago
What is the percent notation for 8/10
nata0808 [166]
80% is your correct answer
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3 years ago
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