Answer:
The answer is below
Step-by-step explanation:
The empirical rules states that for a normal distribution, 68% of the data falls within one standard deviation from the mean, 95% falls within two standard deviation from the mean and 99.7% falls within three standard deviations from the mean.
Given that:
mean (μ) = 71 inches, standard deviation (σ) = 4.3 inches
One standard deviation = μ ± σ = 71 ± 4.3 = (66.7, 75.3)
Two standard deviation = μ ± 2σ = 71 ± 2*4.3 = (62.4, 79.6)
Three standard deviation = μ ± 3σ = 71 ± 3*4.3 = (58.1, 83.9)
The graph is attached
<span>2.8 x 10^6 N
We have 9.8 x 10^7 J or 9.8 x 10^7 kg*m^2/s^2 of work done through a distance of 35 meters. Since work is defined as force over distance, that means that:
F * 35m = 9.8 x 10^7 kg*m^2/s^2
Solving for F, gives
F * 35m = 9.8 x 10^7 kg*m^2/s^2
F = 9.8 x 10^7 kg*m^2/s^2 / 35m
F = 2.8 x 10^6 kg*m/s^2
F = 2.8 x 10^6 N
So the force exerted by the tugboat is 2.8x10^6 Newtons.</span>