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katen-ka-za [31]
3 years ago
5

04/17: Average: Mean

Mathematics
2 answers:
Ainat [17]3 years ago
3 0

Answer:

dam

Step-by-step explanation:

Norma-Jean [14]3 years ago
3 0
Answer: 72 I believe....
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A pile of sand has been stored in the shape of a cone. Mr. Terwilliker knows that the pile is 20 feet tall and 102 feet in circu
xenn [34]

Answer:

The area of tarpaulin is 1315.63 ft^2.  

Step-by-step explanation:

height, h = 20 feet

circumference, C = 102 feet

Let the radius is r.

Circumference, C = 2 x 3.14 x r = 102

r = 16.24 feet

Let the slant height is L.

L = \sqrt{h^2 + r^2}\\\\L = \sqrt{20^2 + 16.24^2}\\\\L = 25.8 ft

The curved surface area is

S = 3.14 x r x L

S = 3.14 x 16.24 x 25.8 = 1315.63 ft^2

4 0
3 years ago
You have 6 reindeer, Rudy, Jebediab, Ezekiel, Lancer, Gloopin, and Balthazar, and you want to have 5 fly your sleigh. You always
Anna71 [15]
You can arrange your reindeer 30 different ways.
5 0
3 years ago
Marie has a small copy of Renny Margaret's famous painting the Schoolmaster her copy has the dimensions of 2 inch by 1.5 in the
Alexandra [31]

Answer:

The answer is 743.4 square inches

Step-by-step explanation:

1. find the length-   2 x 40=80 cm

2. find the width-  1.5 x 40= 60cm

3. find area (Length x width)-  80 x 60= 4800 square cm

4. find length but in inches-   1in=2.54cm  length=80/2.54 = 31.5 inches

5. find width but in inches-  width= 60/2.54= 23.6 inches

6. Find area(length x width)-  31.5 x 23.6= 743.4 square inches

6 0
3 years ago
A rectangular vegetable garden will have a width that is 4 feet less than the length, and an area of 140 square feet. If x repre
UNO [17]

Answer:

The length of the garden=14 feet

Step-by-step explanation:

<em>Step 1: Determine the dimensions of the garden</em>

length of the garden=x feet

width of the garden=(x-4) feet

<em>Step 2: Determine the area of the garden</em>

Area of the garden=length×width

where;

area=140

length=x

width=x-4

replacing'

x(x-4)=140

x²-4x-140=0, solve the quadratic equation;

x={-b±√(b²-4ac)}/2a

x={4±√4²-4×1×-140}/2×1

x={4±√(16+560)}/2

x={4±√576}/2

x=(4±24)/2

x=(4+24)/2=14, or (4-24)/2=-10, take x=14

The length=14 feet, width=(14-4)=10 feet

The length of the garden=14 feet

8 0
3 years ago
Find the highest common factor using prime factorization for 27y and 54y³<br>​
amid [387]

Given:

27y and 54y³

​To find:

The highest common factor (HCF) using prime factorization.

Solution:

We have,

27y and 54y³

Using the prime factorization, we get

27y=3\cdot 3\cdot 3\cdot y

54y^3=2\cdot 3\cdot 3\cdot 3\cdot y\cdot y\cdot y

Now, the common prime factors are 3, 3, 3 and y. So,

HCF=3\cdot 3\cdot 3\cdot y

HCF=27y

Therefore, the highest common factor of the given terms is 27y.

5 0
3 years ago
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