Answer: 20 km
Step-by-step explanation: Let's assume a trajectory of Ships A (which is moving at 6 km/h) and B (which is moving at 4 km/h)
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A 10 km B
And let's assume that who is going to the right is the positive.
Space (S) = S₀ + vt
For A, its space is SA = 0 + 6t
For B, its space is SB = 10 - 4t
They meet at SA = SB;
6t = 10 - 4t
6t + 4t = 10
10t = 10
t = 1h
If the bird is at 20 km/h and it will fly for 1h, it will travel 20 km
Answer:
y= -2/10 +2
Step-by-step explanation:
Answer:
40
Step-by-step explanation:
Angle Formed by Tangent and Secant
= 1/2 (DIFFERENCE of Intercepted Arcs)
< WVT = 1/2 ( WT - UW)
3x+4 = 1/2 (( 14x +7) - (7x+11))
Distribute
3x+4 = 1/2 ( 14x +7 - 7x-11)
Combine like terms
3x+4 = 1/2 ( 7x -4 )
Multiply each side by 2
6x +8 = 7x-4
Subtract 6x from each side
+8 = x-4
Add 4 to each side
12 =x
WVT = 3x+4
= 3*12 +4
= 36+4
= 40
Answer:
D
Step-by-step explanation:
each angle of the triangle is 95° and the second angle has to be in alphabetical order
Answer: The area of the triangle is: " 2v⁴u² square units" ;
or, write as: " 2v⁴u² units² " .
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<u>Note</u>: The formula/equation for the area, "A", of a triangle is:
A = (1/2) * b * h ; or: A = (b * h) / 2 ;
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in which: "A" = "area" ;
"b" = "base length" ;
"h" = "[perpendicular] height" ;
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We are asked to solve for the area, "A" .
We are given: "b = 4v³ " ; "h = vu² " ;
So; to find the area, "A", of the triangle, we plug these given values into the formula; and solve/ simplify:
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A = (1/2) * b * h ;
A = (1/2) * (4v³) * (vu²) ;
A = 2v³ * vu² ;
A = 2v⁴u² square units.
Answer: The area of the triangle is: " 2v⁴u² square units" ;
or, write as: " 2v⁴u² units² " .
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