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3 years ago

I don't get what I'm spose to put on it also how do you work this app I'm new

Mathematics

1 answer:

stiks02 [169]3 years ago

4 0

I'm new too, but I'm pretty sure if you have a question then you ask it, attach a picture if needed, and people might see it and answer.

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Don't understand this at all, please help!

stiks02 [169]

For number 4, the midpoint is M, so the lengths of the 2 segments are half of the whole. PM and MQ are 11.

For number 5, TM and MS are 7.5.

Have an amazing day :)

8 0

3 years ago

Solve the system y = -x + 7 and y = -0.5(x - 3)^2 + 8.

AlladinOne [14]

Answer:

(1,6) & (7,0)

Step-by-step explanation:

y = -x + 7

y = -0.5(x - 3)² + 8

To solve the system, solve these two equations simultaneously

-x + 7 = -0.5(x - 3)² + 8

-x + 7 = -0.5(x² - 6x + 9) + 8

-x + 7 = -0.5x² + 3x - 4.5 + 8

0.5x² - 4x + 3.5 = 0

x² - 8x + 7 = 0

x² - 7x - x + 7 = 0

x(x - 7) - (x - 7) = 0

(x - 1)(x - 7) = 0

x = 1, 7

y = -1 + 7 = 6

y = -7 + 7 = 0

(1,6) (7,0)

Since the system has two distinct solutions, the line and the curve meet at two distinct poibts9: (1,6) & (7,0)

8 0

3 years ago

What is the simplified form of

umka21 [38]

<em>Note: Your answer choices remain a little unclear. But, I have solved the concept and solution, so you can easily figure it out.</em>

Answer:

$\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)=13x^2-2x-4$

Step-by-step explanation:

Given the expression

$\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)$

solving the expression

$=-7x^0+5x^2-x+6-\left(-8x^2+x+3\right)$

apply the rule: $a^0=1,\:a\ne \:0$

$=-7+5x^2-x+6-\left(-8x^2+x+3\right)$

$=-7+5x^2-x+6+8x^2-x-3$

simplify

$=13x^2-2x-4$

Therefore, the simplified form is:

$\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)=13x^2-2x-4$

<em>Note: Your answer choices remain a little unclear. But, I have solved the concept and solution, so you can easily figure it out.</em>

8 0

3 years ago

The product of two irrational numbers is. Rational

Snowcat [4.5K]

Answer:

So the statement:

"The product of two irrational numbers is rational." is false.

Step-by-step explanation:

The product of two irrationals can be irrational or rational.

Example:

$\sqrt{2} \cdot \sqrt{2}=2$

$\sqrt{2}$ is irrational but when you multiply it to itself the output is rational.

Example:

$\sqrt{2} \cdot \sqrt{3}=\sqrt{6}$

$\sqrt{2} \text{ and } \sqrt{3}$ are irrational and when you multiply them you get an irrational answer of $\sqrt{6}$ .

So the statement:

"The product of two irrational numbers is rational." is false.

5 0

3 years ago

A box of pencils costs $10.The total cost (c) as a function of the number of boxes (b) is expressed as c = f(b) = 10b. What is t

Wittaler [7]

Answer:

Domain (b) = {0, 1, 2, 3, 4....}

Set of all whole numbers

Step-by-step explanation:

Given: A box of pencils costs $10.

Total cost (c) = 10b, where "b" is the number of boxes.

Here c represents the range which is dependent variable and b represents the number of boxes which is independent variable.

For instance, if you buy 10 boxes of pencils, you need to pay = 10(10) = $100

Here we replace b with the number of boxes.

The number of boxes cannot be negative. It will star from 0,1, 2, 3....

Therefore, domain (b) = {0, 1, 2, 3, 4....} which is set of whole numbers.

8 0

3 years ago

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