We have that
csc ∅=13/12
sec ∅=-13/5
cot ∅=-5/12
we know that
csc ∅=1/sin ∅
sin ∅=1/ csc ∅------> sin ∅=12/13
sec ∅=-13/5
sec ∅=1/cos ∅
cos ∅=1/sec ∅------> cos ∅=-5/13
sin ∅ is positive and cos ∅ is negative
so
∅ belong to the II quadrant
therefore
<span>the coordinates of point (x,y) on the terminal ray of angle theta are
</span>x=-5
y=12
the answer ispoint (-5,12)
see the attached figure
Answer/Step-by-step explanation:
7. Line 1 = undefined.
Slope of a vertical line is always undefined. The run is zero as x-coordinate remains the same.
8. Line 2 = 




9. Line 3 = 




10. Line 4 = undefined (slope of a vertical line is always undefined)
11. Line 5 = 



12. Line 6 = 




13. Line 7 = 0
An horizontal line has no rise.
14. Line 8 = 0 (slope of horizontal line is always zero)
15. Line 9 = undefined (slope of a vertical line is always undefined)
16. Line 10 = undefined (slope of a vertical line is always undefined)
17. Line 11 = 0 (slope of horizontal line is always zero)
18. Line 12 = undefined (slope of a vertical line is always undefined)
____________________________False
Hello,
Angles y and 3y+8 are supplementaries since the quadrilater is inscribed
y+3y+8=180
==>4y=172
==>y=43 (°)
You could add them on a number line or count on your fingers.