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Ivanshal [37]
3 years ago
14

I need help. With this p

Mathematics
1 answer:
iogann1982 [59]3 years ago
6 0

a_n=a_1+(n-1)d - the formula of n-th term of an arithmetic sequence.

We have:

a_5=12.4;\ a_9=22.4

a_9-a_5=(9-5)d\to4d=22.4-12.4\\\\4d=10\ \ \ \ |:4\\\\d=2.5

a_{31}=a_9+(31-9)d\to a_{31}=22.4+22\cdot2.5=77.4

Answer: C. 77.4

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\bf X=X\qquad thus\qquad \implies \cfrac{24000}{a}=\cfrac{36000}{b}\implies \cfrac{24000}{a}=\cfrac{36000}{\boxed{3+a}} \\\\\\ (3+a)24000=36000a\implies \cfrac{3+a}{a}=\cfrac{36000}{24000}\implies \cfrac{3-a}{a}=\cfrac{3}{2} \\\\\\ 6-2a=3a\implies 6=5a\implies \cfrac{6}{5}=a\implies 1\frac{1}{5}=a\implies \blacktriangleright 1.2 = x\blacktriangleleft

\bf \stackrel{\textit{since we know that}}{b=3+a}\implies b=3+\cfrac{6}{5}\implies b=\cfrac{21}{5}\implies b=4\frac{1}{5}\implies \blacktriangleright b=4.2 \blacktriangleleft

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