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miskamm [114]
3 years ago
12

*Simple math question* The eighth grade class at grade school has 15 girls and 14 boys. How many different boy-girl dates can be

arranged?
Mathematics
1 answer:
AlladinOne [14]3 years ago
3 0
15*14=210
210 boy-girl dates
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1. "The sum of a number and 4.
Norma-Jean [14]

Answer:

a+4=

Step-by-step explanation:

7 0
3 years ago
0.18(y-9)+0.06y=0.04y-0.9
Ksju [112]
Simplify both sides then isolate the variable and it gives you y=3.6
7 0
3 years ago
Complete the equation 0.037 x ? = 37 pls hurry
OleMash [197]

Answer:

The missing number is 1000

Step-by-step explanation:

0.037 × ? = 37

Divide both sides by 0.037.

a = \frac{37}{0.037}

Expand \frac{37}{0.037} by multiplying both the numerator and the denominator by 1000.

a = \frac{37000}{37}

Divide 37000 by 37 to get 1000.

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Hope it helps and have a great day! =D

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4 0
2 years ago
Please please please help.​
saul85 [17]

Answer:

Step-by-step explanation:

(-5,-3) is a point on the graph.

f⁻¹(-3) = -5

7 0
3 years ago
What is the value of K?
Ksju [112]
Answer: The value of k for which one root of the quadratic equation kx2 - 14x + 8 = 0 is six times the other is k = 3.
Let's look into the solution step by step.

Explanation:

Given: A quadratic equation, kx2 - 14x + 8 = 0

Let the two zeros of the equation be α and β.

According to the given question, if one of the roots is α the other root will be 6α.

Thus, β = 6α

Hence, the two zeros are α and 6α.

We know that for a given quadratic equation ax2 + bx + c = 0

The sum of the zeros is expressed as,

α + β = - b / a

The product of the zeros is expressed as,

αβ = c / a

For the given quadratic equation kx2 - 14x + 8 = 0,

a = k, b = -14, c = 8

The sum of the zeros is:

α + 6α = 14 / k [Since the two zeros are α and 6α]

⇒ 7α = 14 / k

⇒ α = 2 / k --------------- (1)

The product of the zeros is:

⇒ α × 6α = 8 / k [Since the two zeros are α and 6α]

⇒ 6α 2 = 8 / k

⇒ 6 (2 / k)2 = 8 / k [From (1)]

⇒ 6 × (4 / k) = 8

⇒ k = 24 / 8

⇒ k = 3
6 0
3 years ago
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