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chubhunter [2.5K]
4 years ago
6

Pete began practice his trumpet at fifteen minutes pass three write this time using AM or PM

Mathematics
2 answers:
MatroZZZ [7]4 years ago
7 0
Pete began practicing
at 3:15 AM
Tcecarenko [31]4 years ago
6 0
A.M 15:15
P.M 3:15

A.m time has to be in a 24 hour clock
P.m can be normal
You might be interested in
Plz help me with this
Nitella [24]

Answer: C) y ≥ 3x - 2;  y\leq \dfrac{1}{2}x+3

<u>Step-by-step explanation:</u>

Blue line:

y-intercept (b) = -2

slope (m) is 3 up, 1 right = 3

shading is above

⇒ y ≥ 3x - 2

Yellow line:

y-intercept (b) = 3

slope (m) is 1 up, 2 right = \dfrac{1}{2}

shading is below

\implies \bold{y\leq \dfrac{1}{2}x+3}

8 0
4 years ago
Help me plz plz plz i will give the brainliest .
Darina [25.2K]

Answer:

-100

Step-by-step explanation:

hope this helps...

5 0
3 years ago
What's the value of 7 in68756
Ivan
700. or the hundredth.
8 0
3 years ago
Two buildings on opposites sides of a highway are 3x^3- x^2 + 7x +100 feet apart. One building is 2x^2 + 7x feet from the highwa
iVinArrow [24]

Given:

Distance between two buildings = 3x^3- x^2 + 7x +100 feet apart.

Distance between highway and one building = 2x^2 + 7x feet.

Distance between highway and second building = x^3 + 2x^2 - 18 feet.

To find:

The standard form of the polynomial representing the width of the highway between the two building.

Solution:

We know that,

Width of the highway = Distance between two buildings - Distance of both buildings from highway.

Using the above formula, we get the polynomial for width (W) of the highway.

W=3x^3- x^2 + 7x +100-(2x^2 + 7x)-(x^3 + 2x^2 - 18)

W=3x^3- x^2 + 7x +100-2x^2-7x-x^3 -2x^2+18

Combining like terms, we get

W=(3x^3-x^3)+(- x^2 -2x^2-2x^2)+ (7x -7x)+(100 +18)

W=2x^3-5x^2+0+118

W=2x^3-5x^2+118

Therefore, the width point highway is 2x^3-5x^2+118.

8 0
3 years ago
The functions q and r are defined as follows
kolezko [41]

Answer:

98

Step-by-step explanation:

So we have the two functions:

g(x)=-2x-2\text{ and } r(x)=x^2-2

And we want to find the value of r(g(4)).

To do so, first find the value of g(4):

g(x)=-2x-2\\g(4)=-2(4)-2\\

Multiply:

g(4)=(-8)-2

Subtract:

g(4)=-10

Now, substitute this into r(g(4)):

r(g(4))\\=r(-10)

And substitute this value into r(x):

r(-10)=(-10)^2-2

Square:

r(-10)=100-2

Subtract:

r(-10)=98

Therefore:

r(-10)=r(g(4))=98

3 0
3 years ago
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