Question

The functions q and r are defined as follows

Answer 1

Answer:

98

Step-by-step explanation:

So we have the two functions:

$g(x)=-2x-2\text{ and } r(x)=x^2-2$

And we want to find the value of r(g(4)).

To do so, first find the value of g(4):

$g(x)=-2x-2\\g(4)=-2(4)-2$

Multiply:

$g(4)=(-8)-2$

Subtract:

$g(4)=-10$

Now, substitute this into r(g(4)):

$r(g(4))\\=r(-10)$

And substitute this value into r(x):

$r(-10)=(-10)^2-2$

Square:

$r(-10)=100-2$

Subtract:

$r(-10)=98$

Therefore:

$r(-10)=r(g(4))=98$