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Lelu [443]
3 years ago
10

I need to know what the solution is and how to solve it

Mathematics
1 answer:
maria [59]3 years ago
4 0

Answer:

35 is the answer of that problem

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A video game maker claims that number of glitches in code for their
svet-max [94.6K]

Answer:

The major condition that needs to be satisfied before a t-test is performed that the question satisfies easily is the use of random sampling to obtain sample data.

Step-by-step explanation:

The major conditions necessary to conduct a t-test about a mean include;

- The sample extracted from the population must be extracted using random sampling. That is, the sample must be a random sample of the population.

- The sampling distribution must be normal or approximately normal. This is achievable when the population distribution is normal or approximately normal.

- Each observation in the sample data must have an independent outcome. That is, the outcome/result of each sub-data mustn't depend on one another.

Of the three conditions that need to be satisfied before the conduction of a t-test, the first condition about using a random sampling technique is evidently satisfied.

It is stated in the question that 'A private investigator hired by a competitor takes a random sample of 47 games and tries to determine if there are more than 7 glitches per game'.

Hope this Helps!!!

5 0
3 years ago
If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be
babymother [125]

Answer:

If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.

Step-by-step explanation:

Here in this question, we want to state what will happen if the null hypothesis is true in a chi-square test.

If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.

This is because at a higher level of discrepancies, there will be a strong evidence against the null. This means that it will be rare to find discrepancies if null was true.

In the question however, since the null is true, the discrepancies we will be expecting will thus be small and common.

8 0
3 years ago
Juan owes his cousin, Benito, $10.00. Benito is tired of waiting for Juan to pay him back. To try and get Juan to pay up more qu
AleksAgata [21]

Answer:

Equation: 10+x= 15 +0.5x

Time: 10 days

Amount: 20$

Step-by-step explanation:

<u>Equation for Benito:</u>

  • 10 + x*1

<u>Equation for Tavon:</u>

  • 15 + x*0.5

<u>Since the sums equalize at some time, we get:</u>

  • 10+x= 15 +0.5x
  • x - 05x = 15- 10
  • 0.5x = 5
  • x= 5/0.5
  • x= 10 days

After 10 days, Juan will owe both Benito and Tavon $20

7 0
3 years ago
A bag contains 20 slips of paper Individually numbered. If a slip of paper and a letter in the word PENNSYLVANIA is chosen at ra
Soloha48 [4]

Answer:

P(M4\ n\ V) = 2.083\%

Step-by-step explanation:

Given

Paper = 20 slips

Word: PENNSYLVANIA

Required

Determine P(Multiple of 4 and V)

The sample size of the 20 slips is:

n(S) = 20

The outcomes of multiples of 4 is:

M4= \{4,8,12,16,20\}

n(M4) = 5

So, the probability of multiples of 4 is:

Pr(M4) = \frac{5}{20}

Pr(M4) = \frac{1}{4}

The sample size of PENNSYLVANIA is:

n(S) = 12

The outcome of V is:

n(V) = 1

So, the probability of V is:

P(V) = \frac{1}{12}

So, the required probability is: P(Multiple of 4 and V)

P(M4\ n\ V) = P(M4) * P(V)

P(M4\ n\ V) = \frac{1}{4} * \frac{1}{12}

P(M4\ n\ V) = \frac{1}{48}

P(M4\ n\ V) = 0.02083

Express as percentage

P(M4\ n\ V) = 0.02083 * 100\%

P(M4\ n\ V) = 2.083\%

4 0
3 years ago
Do you know what 2/9 x 3 is?
ohaa [14]

Answer:

answer =  \frac{2}{3}

\frac{2}{9}  \times  \frac{3}{1}  \\   =  \frac{6}{9}  =  \frac{2}{3}

7 0
3 years ago
Read 2 more answers
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