When you have something like this, all you need to do is substitute the values, the last is for what value of x
For the first one;
((x^2+1)+(x-2))(2)
(x^2+x-1)(2)
(2)^2+(2)-1
4+2-1
5
For the second one;
((x^2+1)-(x-2))(3)
(x^2-x+3)(3)
(3)^2-(3)+3
9-3+3
9
For the last one;
3(x^2+1)(7)+2(x-2)(3)
3((7)^2+7)+2((3)-2)
3(49+7)+2(3-2)
3(56)+2(1)
168+2
170
m<3 =72°
This is because m<1 and m<3 are vertically opposite.
Answer:
4,391
Step-by-step explanation:
next time use a caculator luv <3
Commutative property of multiplication is what the property is called.
A * B = B * A
Where both 'A' and 'B' are expressions.
Hope this helps!
