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3 years ago

Three differences between prokaryotic and eukaryotic cells

Biology

2 answers:

pogonyaev3 years ago

6 0

Eukaryotic eat i believe ?? check ur sources

viva [34]3 years ago

5 0

The main difference between prokaryotic and eukaryotic cells is that eukayrotic cells have a nucleus and membrane-bound organelles, while prokaryotic cells lack these structures.
Prokaryotes and eukaryotes also differ in terms of cell size.
While prokaryotic cells do not contain membrane-bound organelles, they do contain ribosomes. However, these are smaller than the ribosomes found in eukaryotic cells.

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Which organic molecules are nucleic acids

Lostsunrise [7]

I think it may be this but not quite sure

Lipids are primarily hydrophobic in nature, but there are a large variety of lipids such as fatty acids, mono-, di-, and triglycerides, for example (check wikipedia for more examples).

Proteins are polymers of amino acids. 

Nucleic acids are polymers of nucleotides.

4 0

3 years ago

2. Dominant trait: cleft chin (C) Mother’s gametes: Cc

andre [41]

.2. Offspring Genotypes will be Cc or cc.

Offspring phenotypes : Cleft chin or no cleft chin.

% chance child will have cleft chin: 50%

3. % chance child will have arched feet: 25%

4. % chance child will have blonde hair: 50%

5. % chance child will have normal vision: 25%

Explanation:

CASE 1 :

Dominant trait: cleft chin (C)

Recessive trait: lacks cleft chin (c)

Father’s gametes: cc

Mother’s gametes: Cc

There are two possible combination of Gametes ,

C fom mother and c from father= Cc

c from mother and c from father = cc

Gametes of Cc Parents= $\frac{1}{2}C + \frac{1}{2} c$ ........(i)

Gametes of cc parents = $\frac{1}{2}c + \frac{1}{2}c$ .........(ii)

Combining (i) and (ii) we get,

$\frac{1}{2} Cc + \frac{1}{2} cc$

There fore offspring Genotypes will be Cc or cc

Offspring phenotypes :

Genotype Cc then phenotype= Cleft chin

Genotype cc then phenotype = Lacks cleft chin.

percentage chance child will have cleft chin = $\frac{0.5}{1}$ ×100

Therefore the chance is 50%.

CASE 2 :

Dominant trait: flat feet (A)

Recessive trait: arched feet (a)

Mother’s gametes: Heterozygous (Aa)

Father’s gametes: Heterozygous (Aa)

There are four possible combination of genotypes are =AA , Aa, Aa and aa

i.e. A from mother, A from father= AA

A from mother, a from father =Aa

a from mother, A from Father = Aa

a from mother, a from father = aa

Gametes of Aa parent = $\frac{1}{2} A + \frac{1}{2} a$

Gametes of other Aa parent = $\frac{1}{2} A + \frac{1}{2} a$

..................................................................................

$\frac{1}{4} AA + \frac{1}{4} Aa$

+ $\frac{1}{4} Aa$ + $\frac{1}{4} aa$

..........................................................................................

$\frac{1}{4}AA + \frac{1}{2}Aa +\frac{1}{4} aa$

Offspring Genotypes will be: AA or Aa or aa

Offsprings phenotype will be:

Genotype AA then phenotype will be Flat feet

Genotype Aa then phenotype will be flat feet

Genotype aa then Phenotype will be arched feet.

Percentage chance child will have arched feet = $\frac{0.25}{1}$ × 100 = 25%

CASE 3:

Dominant trait: Brown hair (B)

Recessive trait: Blonde hair (b)

Mother’s gametes: Homozygous recessive (bb)

Father’s gametes: Heterozygous (Bb)

This case is very similar to the case 1 as one parent is homozygous recessive and other parent is heterozygous.

Resulting in half Bb and halve bb combination.

Genotypes will be Bb or bb

Phenotypes will be :

Genotype Bb then phenotype Brown hair

Phenotype bb then Phenotype bb.

% chance child will have blonde hair: 50%

CASE 4:

Dominant trait: farsightedness (F)

Recessive trait: normal vision (f)

Mother’s gametes: Heterozygous (Ff)

Father’s gametes: Heterozygous (Ff)

This Case is similar to case 2

it will result in one-fourth FF , half Ff and one-fouth ff combination.

Therefore Genotypes will be: FF, Ff and ff

Phenotypes:

Genotype FF then phenotype farsightedness

Genotype Ff then phenotype farsightedness

Genotype ff then phenotype normal vision.

% chance child will have normal vision: 25%

3 0

3 years ago

1. Which of the following are located in the

zimovet [89]

Answer:

Your answer would be A. GENES

Explanation:

3 0

2 years ago

why is it a good idea for a bacterial cell to be abel to use glucose first as an energy source then switch to lactose

olchik [2.2K]

Answer:

Due to less steps and requires less energy.

Explanation:

The bacterial cell is able to use glucose first as an energy source then switch to lactose because glucose requires less steps and less amount of energy for the break down as compared to lactose. If lactose is the only sugar available to the bacterial cells, then bacterial cells will use it as energy source for the production of energy. In order to use lactose, the bacteria must express the lac operon genes, which encode the main enzymes for lactose uptake and metabolism.

8 0

2 years ago

What will charles darwin have to say about lamarcks theory?

iragen [17]

He would say that Lamarck's theory is wrong. Lamarck's theory stated that traits that are used are passed on to the offspring. In other words, if an organism changes during its lifetime in order to adapt to its environment, then its changes will be passed on to its offspring. This is wrong because this means that organisms pass on traits based on genetic information and not based on the environment of the offspring.

Hope this helps.

8 0

3 years ago