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arlik [135]
3 years ago
9

How many rectangular tables would be necessary to seat 256 people at 12 seats per person?

Mathematics
1 answer:
lesya692 [45]3 years ago
4 0
If you need to seat 256 people, and each table sits 12 people, then take 256 / 12 to find your answer.

256 / 12 = 21.33
Since it's a bit over 21, you're going to need 22 tables. 
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How do you solve (a-3b)(7a-3b)
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Step-by-step explanation:

Simplifying

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((7a * 7a + -3b * 7a) + 3b * (7a + -3b)) = 0

Reorder the terms:

((-21ab + 49a2) + 3b * (7a + -3b)) = 0

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(-21ab + 49a2 + (7a * 3b + -3b * 3b)) = 0

(-21ab + 49a2 + (21ab + -9b2)) = 0

Reorder the terms:

(-21ab + 21ab + 49a2 + -9b2) = 0

Combine like terms: -21ab + 21ab = 0

(0 + 49a2 + -9b2) = 0

(49a2 + -9b2) = 0

Solving

49a2 + -9b2 = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '9b2' to each side of the equation.

49a2 + -9b2 + 9b2 = 0 + 9b2

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49a2 = 0 + 9b2

Remove the zero:

49a2 = 9b2

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a2 = 0.1836734694b2  

Simplifying

a2 = 0.1836734694b2

take the square root of each side:

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3 years ago
Read 2 more answers
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JulsSmile [24]

Answer:

13:30

Step-by-step explanation:

120 minutes is 2 hr so 11:30 +2:00= 13:30

7 0
3 years ago
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Bond [772]

Answer:

(a) You will get ten

Step-by-step explanation:

single cell = 3 min

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3 0
3 years ago
I need fast help with step by step<br> <img src="https://tex.z-dn.net/?f=%5Cint%5Climits%5E2_1%20%7B%5Cfrac%7B3x-1%7D%7Bx%2B1%7D
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4 years ago
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