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3 years ago

Shout is to yell as brag is to

Advanced Placement (AP)

2 answers:

Effectus [21]3 years ago

7 0

Brag is to show off your stuff or think your the best

nasty-shy [4]3 years ago

4 0

Brag is to show off

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O tema do texto e

slega [8]

Answer:

Explanation:

uiljlrdfhgj';l;kfjhk,./

6 0

3 years ago

When the number of workers in an occupation is limited and demand for these workers is high, then wages tend to be a variable b

sergey [27]

Answer: high

Explanation:

When the supply of labor for a particular occupation is high, this means that there are plenty people who are ready to work and there's surplus labor. When the need for workers arise by employers, due to the high labor supply, there'll be lower wages that'll be offered to them.

On the other hand, when the number of workers that we have in an occupation is limited and the demand for such workers is high, this will bring about a scenario whereby the wages that'll be offered to such workers will be high because there's a high demand for them and there are limited workers for that occupation.

7 0

3 years ago

Which pairs of figures are similar polygons?

Pepsi [2]

All except the triangles

4 0

3 years ago

Read 2 more answers

)I want to add 16 mph to my fastball so I can enter major league baseball right out of high school. What change would make this

Alex73 [517]

Answer: A

Explanation: If you make it a deadline driven you push yourself to get that goal because you know you have a end date

6 0

3 years ago

I can’t figure this problem out

Natalka [10]

Answer:

Explanation:

Alright so the way to do this is to use properties of integrals to make our life easier.

So we have:

$\int\limits^4_1 {(3f(x)+2)} \, dx$

So lets break this up into two different integrals that represent the same area.

$\int\limits^4_0 {f(x)} \, dx - \int\limits^1_0 {f(x)} \, dx = \int\limits^4_1 {f(x)} \, dx$

Lets think about what is going on up there. The integral from four to zero gives us the area under the curve of f(x) from four to zero. If we subtract this from the integral from one to zero (the area under f from one to zero) we are left with the area under f from four to one! Hence:

$\int\limits^4_1 {f(x)} \, dx$

But since we have these values we can say that:

-3 - 2 = -5

Which means that $\int\limits^4_1 {f(x)} \, dx$ = -5

So now we can evaluate $\int\limits^4_1 {(3f(x)+2)} \, dx$

Lets first break up our integrand into two integrals

$\int\limits^4_1 {(3f(x)+2)} \, dx$ = $3\int\limits^4_1{f(x)} \, dx + 2\int\limits^4_1 {} \, dx$

Now we can evaluate this:

We know that $\int\limits^4_1 {f(x)} \, dx$ = -5

So:

$3(-5)+2[x]$ where x is evaluated at 4 to 1 so

-15 + 2(3)

So we are left with -15 + 6 = -9

5 0

3 years ago