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3 years ago

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A feral cat needs to eat two mice a day to survive. A mouse needs to eat 5 seeds a day to survive. How many seeds are required t

o feed a feral cat for a week (7 days)?

1 answer:

Mars2501 [29]3 years ago

3 0

Answer:

70 seeds

Explanation

5 is the food for a mouse (day)x2 mice for cat=10. 10x7(week)=70 seeds

hope this helps!

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What is the magnitude of the force exerted by the biceps fbiceps? What is the magnitude of the force exerted by the elbow felbow

Slav-nsk [51]

Answer:

<u> </u><u>The magnitude of the force exerted by the biceps </u> $f_b_i_c_e_p_s$ <u> is 218.38N</u>

<u>The magnitude of the force exerted by the elbow </u> $f_e_l_b_o_w$ <u> is 194.37N</u>

Explanation:

Firstly , lets calculate the magnitude of force exerted by biceps $f_b_i_c_e_p_s$ -

Mass of the forearm=

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= 0.950kg

so, weight of the forearm=

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weight of the ball=

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Now , balancing torque about the elbow , we have-

$F_b_i_c_e_p_s\times d_b_i_c_e_p_s= w_f\times\frac{d_b_a_l_l}{2} + w_b_a_l_l\times d_b_a_l_l$

(here , distance of the bicep is 2.50cm = 0.025m and distance of the ball is 36cm= 0.36m)

Now putting the given values in the formula -

$F_b_i_c_e_p_s\times 0.025= 0.95\times9.8\times\frac{0.36}{2} +1.50\times 0.36$

$F_b_i_c_e_p_s=218.38N$

Now, lets calculate the force exerted by elbow $F_e_l_b_o_w$ -

Balancing the vertical forces

$F_b_i_c_e_p_s=F_e_l_b_o_w+w_f+w_b_a_l_l$

$F_e_l_b_o_w = 218.38-(1.00\times9.8)-(0.95\times9.8)$

$F_e_l_b_o_w=194.37N$

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