3 years ago

Can someone help me with college algebra?

Mathematics

1 answer:

makkiz [27]3 years ago

7 0

Whats the problem that you need help with

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If the sales tax for the city of Los Angeles is 9.75%, how much tax would you pay for an item that costs $200.00?

Natalka [10]

200*0.0975= $19.50 would be the answer

5 0

2 years ago

Read 2 more answers

PLEASE HELP!!

erik [133]

$2.=c.\\\\2\sin4x\cos4x=2\sin(2\cdot4x)=2\sin8x\\\\Used:\\\sin2\alpha=2\sin\alpha\cos\alpha$

$1.=b.\\\\\csc x-\sin x=\dfrac{1}{\sin x}-\dfrac{\sin^2x}{\sin x}=\dfrac{1-\sin^2x}{\sin x}=\dfrac{\cos^2x}{\sin x}\\\\=\dfrac{\cos x\cos x}{\sin x}=\cos x\cdot\dfrac{\cos x}{\sin x}=\cos x\cot x\\\\Used:\\\csc x=\dfrac{1}{\sin x}\\\\\sin^2x+\cos^2x=1\to\cos^2x=1-\sin^2x\\\\\cot x=\dfrac{\cos x}{\sin x}$

$3.=a.\\\\\dfrac{\sin x-1}{\sin x+1}=\dfrac{\sin x-1}{\sin x+1}\cdot\dfrac{\sin x+1}{\sin x+1}=\dfrac{\sin^2x-1^2}{(\sin x+1)^2}=\dfrac{\sin^2x-1}{(\sin x+1)^2}\\\\=\dfrac{-(1-\sin^2x)}{(\sin x+1)^2}=\dfrac{-\cos^2x}{(\sin x+1)^2}\\\\Used:\\(a-b)(a+b)=a^2-b^2\\\\\sin^2x+\cos^2x=1\to \cos^2x=1-\sin^2x$

8 0

3 years ago

Hey guys I need help! I'm having so much trouble with understanding this...

Aleonysh [2.5K]

What part do you have trouble with

8 0

2 years ago

Alexander purchased a computer on sale. The original price was $1,200. The sale price was 5/6 of the original price. How much di

gtnhenbr [62]

1160 dollars if you take 5/6 away from 1200 you get 40 subtract 40 from 1200 and you get your answer

6 0

3 years ago