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3 years ago

9

On August 10, 1936, a temperature of 120ºF. was recorded un Ponds, Arkansas. On Febrery 13, 1905, Ozark, Arkansas, recorded a te

mperature of -29ºF. What is the difference between these two temperatures?

2 answers:

Margarita [4]3 years ago

4 0

Answer:

47

Step-by-step explanation:

Dominik [7]3 years ago

3 0

Answer:

is this cold for - Febrery for August this 120 F

Step-by-step explanation:

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snow_lady [41]

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Polly bought a new collar and leash for her dog. The total was $7.50. She paid with a ten-dollar bill.

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2 years ago

Simplify (b^4)^3 A.B^9 B.B^3 C.B D.B^12

natulia [17]

(b^4)^3

To simplify when something is raised to two different exponents, multiply the two exponents together:

4 * 3 = 12

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3 years ago

What numbers are zeros of g(x) = x^2 - 2x - 4? take your time if you need to!

ipn [44]

Answer:

$x = 1 + \sqrt5, x = 1 - \sqrt5$

Step-by-step explanation:

Hello!

We can solve the quadratic by using the quadratic formula.

Standard form of a quadratic: $ax^2 + bx + c = 0$

Quadratic Formula: $x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}$

Given our Equation: $g(x) = x^2 - 2x - 4$

a = 1
b = -2
c = -4

Plug the values into the equation and solve.

<h3>Solve</h3>

$x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}$
$x = \frac{-(-2)\pm\sqrt{(-2)^2 - 4(1)(-4)}}{2(1)}$
$x = \frac{2\pm\sqrt{4 +16}}{2}$
$x = \frac{2\pm\sqrt{20}}{2}$
$x = \frac{2\pm\sqrt{4 * 5}}{2}$
$x = \frac{2\pm(\sqrt4 * \sqrt5)}{2}$
$x = \frac{2\pm2\sqrt5}{2}$
$x = 1 + \sqrt5, x = 1 - \sqrt5$

7 0

2 years ago

Only 6 of the 75 trees in a park are at least 30 feet tall. What percent of the trees are under 30 feet tall?

wariber [46]

Percentage of tress under 30 = 6/75 x 100 = 8%

Answer: 8%

6 0

3 years ago