Answer:
Let's define the variables:
A = price of one adult ticket.
S = price of one student ticket.
We know that:
"On the first day of ticket sales the school sold 1 adult ticket and 6 student tickets for a total of $69."
1*A + 6*S = $69
"The school took in $150 on the second day by selling 7 adult tickets and student tickets"
7*A + 7*S = $150
Then we have a system of equations:
A + 6*S = $69
7*A + 7*S = $150.
To solve this, we should start by isolating one variable in one of the equations, let's isolate A in the first equation:
A = $69 - 6*S
Now let's replace this in the other equation:
7*($69 - 6*S) + 7*S = $150
Now we can solve this for S.
$483 - 42*S + 7*S = $150
$483 - 35*S = $150
$483 - $150 = 35*S
$333 = 35*S
$333/35 = S
$9.51 = S
That we could round to $9.50
That is the price of one student ticket.
Answer:
{3-i, 3+ i}
Step-by-step explanation:
hello : the equation is : x²-6x+10 =0
because : (3+i)²-6(3+i)+10 = 9+6i+i²-18-6i+10 =9+6i-1-18-6i+10 =0...right
same method for 3-i... (all quadratic equation have two conjugate solution)
Answer:
4
hours
i hope that helped
Step-by-step explanation:
Answer:
I think you are right
Step-by-step explanation:
Answer: (5, 12)
Step-by-step explanation:
Just graph the linear equations and find where they intersect.
Algebraically, you can set them equal to each other
-3x-3=2x+2
-x-3=2
-x=5
x=5
Plug x=5 to any equation
y=2(5)+2
y=12
