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Licemer1 [7]
3 years ago
9

(3.6x10^-5)/(1.8x10^2)

Mathematics
2 answers:
Vika [28.1K]3 years ago
8 0

Answer:

2x10^-7

Step-by-step explanation:

Thankyou

vovikov84 [41]3 years ago
3 0

Answer:

The answer is 20000

Hope it helps..

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Solve the inequality<br> d-6&gt;-4
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D-6>-4
+6 both sides
d>2
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Which figure is the pre-image? Which figure is the image after the first transformation? Which figure is the image after the sec
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I believe the red one is the first image then the blue then the green because they show the prime sign

Step-by-step explanation:

4 0
3 years ago
Using PYTHAGORAS THEOREM answer the question A vertical pillar ab bent at c at a height of 2.4m and its upper end b touches the
Alisiya [41]

Answer:

  5.4 m

Step-by-step explanation:

The Pythagorean theorem tells you the relationship between the various lengths is ...

  cd² = ac² +ad²

  cd² = (2.4 m)² + (1.8 m)² = 9.00 m²

  cd = √(9.00 m²) = 3.0 m

Since cd = cb and ab = ac+cb, we have ...

  ab = 2.4 m + 3.0 m = 5.4 m

_____

You may recognize this as a 3-4-5 right triangle with a scale factor of 0.6. We are asked for the sum of the lengths of the "4" and "5" legs, which is ...

  0.6·(4+5) = 5.4

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How do I solve y+5x=2;-1,0,1 ?
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Each of 16 students measured the circumference of a tennis ball by four different methods, which were: A: Estimate the circumfer
almond37 [142]

Answer:

Following are the solution to the given equation:

Step-by-step explanation:

Please find the complete question in the attachment file.

In point a:

\to \mu=\frac{\sum xi}{n}

       =22.8

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{119.18}{16-1}}\\\\ =\sqrt{\frac{119.18}{15}}\\\\ = \sqrt{7.94533333}\\\\=2.8187

In point b:

\to \mu=\frac{\sum xi}{n}

       =20.6875  

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{26.3375}{16-1}}\\\\=\sqrt{\frac{26.3375}{15}}\\\\ =\sqrt{1.75583333}\\\\ =1.3251

In point c:

 \to \mu=\frac{\sum xi}{n}

         =21  

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{2.62}{16-1}}\\\\ =\sqrt{\frac{2.62}{15}} \\\\= \sqrt{0.174666667}\\\\=0.4179

In point d:

\to \mu=\frac{\sum xi}{n}

       =20.8375  

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{8.2975}{16-1}}\\\\ =\sqrt{\frac{8.2975}{15}} \\\\  =\sqrt{0.553166667} \\\\ =0.7438

6 0
3 years ago
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